18) Heat Transfer: Our friend Dr. Giancoli is caught in an afternoon blizzard near the top of Mt. Dana, and fortunately has a down jacket with _0.05 m thick down insulation k = 6 x 10–©kCal/(s m C°) covering a body area of 1.5 m². His body temperature is _38°C and the outside temperature is –12°C. How much heat is he losing per hr? (1 hr =3600s) (a Cliff bar is 250kCal, so he can last a while) 8.1 kCal k=6x 10-6 kCal/(s m °C) A Dr. Giancoli =1.5 m ² 16.2 kCal | 0.05 m 32.4 kCal 64.8 kCal Dr. Giancoli -12°C
18) Heat Transfer: Our friend Dr. Giancoli is caught in an afternoon blizzard near the top of Mt. Dana, and fortunately has a down jacket with _0.05 m thick down insulation k = 6 x 10–©kCal/(s m C°) covering a body area of 1.5 m². His body temperature is _38°C and the outside temperature is –12°C. How much heat is he losing per hr? (1 hr =3600s) (a Cliff bar is 250kCal, so he can last a while) 8.1 kCal k=6x 10-6 kCal/(s m °C) A Dr. Giancoli =1.5 m ² 16.2 kCal | 0.05 m 32.4 kCal 64.8 kCal Dr. Giancoli -12°C
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Transcribed Image Text:18) Heat Transfer: Our friend Dr. Giancoli is caught in an afternoon blizzard near the top of Mt.
Dana, and fortunately has a down jacket with 0.05 m thick down insulation k = 6 x 10-6kCal/(s m C°)
covering a body area of 1.5 m². His body temperature is 38°C and the outside temperature is –12°C.
How much heat is he losing per hr? (1 hr =3600s) (a Cliff bar is 250kCal, so he can last a while)
8.1 kCal
k=6x 10-6 kCal/(s m °C)
A
Dr. Giancoli
=1.5 m?
16.2 kCal
0.05 m
32.4 kCal
64.8 kCal
Dr.
Giancoli
-12°C
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