please #### Problem 18A solid uniform disk (I = 0.5mr²) is rolling without slipping along a horizontal surface with a speed of 4.5 m/s when it starts up a ramp that makes an angle of 25° with the horizontal. What is the correct expression for the final speed of the disk after it has rolled 3.0 m up as measured along the surface of the ramp?#### Options:A) \[ 5/4[(4/3)v_i^2 - 3gcos25°]^{1/2} \]B) \[ 5/4[(4/3)v_i^2 - 3gsin25°]^{1/2} \]C) \[ 3/4[(4/3)v_i^2 - 3gcos25°]^{1/2} \]D) \[ 4/3[(3/4)v_i^2 - 3gsin25°]^{1/2} \]E) \[ 3/4[(4/3)v_i^2 - 3gsin25°]^{1/2} \]#### Answer Choices:- A- B- C- D- E This question is related to the principles of rotational motion and energy conservation for a rolling object. The scenario describes a disk transitioning from horizontal motion to motion up an incline, involving the potential and kinetic energy components to derive the final speed. The key variables include the moment of inertia of the disk, initial speed (4.5 m/s), the angle of the incline (25°), and the distance traveled up the incline (3.0 m).The correct answer should consider both translational and rotational kinetic energy along with potential energy changes.

Answered: Image /qna-images/answer/5ce83967-50fa-46c2-a899-112931c13418.jpg

18) A solid uniform disk (1=0.5mr²) is rolling without slipping along a horizontal surface with a speed of 4.5 m/s when it starts up a ramp that makes an angle of 25° with the horizontal. What is the correct expression for the final speed of the disk after it has rolled 3.0 m up as measured along the surface of the ramp? A) [5/4((4/3)V2 - 3gcos25%)]1/2 B) [5/4((4/3)V2 - 3gsin25011/2 C) [3/4((4/3)V2-3gcos25%)]1/2 D) [4/3((3/4)V2 - 3gsin250) 11/2 E) [3/4((4/3)V2-3gsin25%)]1/2 OA OB OC OD OE

18) A solid uniform disk (1=0.5mr²) is rolling without slipping along a horizontal surface with a speed of 4.5 m/s when it starts up a ramp that makes an angle of 25° with the horizontal. What is the correct expression for the final speed of the disk after it has rolled 3.0 m up as measured along the surface of the ramp? A) [5/4((4/3)V2 - 3gcos25%)]1/2 B) [5/4((4/3)V2 - 3gsin25011/2 C) [3/4((4/3)V2-3gcos25%)]1/2 D) [4/3((3/4)V2 - 3gsin250) 11/2 E) [3/4((4/3)V2-3gsin25%)]1/2 OA OB OC OD OE

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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please

#### Problem 18
A solid uniform disk (I = 0.5mr²) is rolling without slipping along a horizontal surface with a speed of 4.5 m/s when it starts up a ramp that makes an angle of 25° with the horizontal. What is the correct expression for the final speed of the disk after it has rolled 3.0 m up as measured along the surface of the ramp?

#### Options:
A) \[ 5/4[(4/3)v_i^2 - 3gcos25°]^{1/2} \]

B) \[ 5/4[(4/3)v_i^2 - 3gsin25°]^{1/2} \]

C) \[ 3/4[(4/3)v_i^2 - 3gcos25°]^{1/2} \]

D) \[ 4/3[(3/4)v_i^2 - 3gsin25°]^{1/2} \]

E) \[ 3/4[(4/3)v_i^2 - 3gsin25°]^{1/2} \]

#### Answer Choices:
- A
- B
- C
- D
- E

This question is related to the principles of rotational motion and energy conservation for a rolling object. The scenario describes a disk transitioning from horizontal motion to motion up an incline, involving the potential and kinetic energy components to derive the final speed. The key variables include the moment of inertia of the disk, initial speed (4.5 m/s), the angle of the incline (25°), and the distance traveled up the incline (3.0 m).

The correct answer should consider both translational and rotational kinetic energy along with potential energy changes.

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