18–51. The uniform garage door has a mass of 150 kg and s guided along smooth tracks at its ends. Lifting is done using the two springs, each of which is attached to the anchor bracket at A and to the counterbalance shaft at B and C. As the door is raised, the springs begin to unwind rom the shaft, thereby assisting the lift. If each spring provides a torsional moment of M=(0.70) N • m, where 0 is n radians, determine the angle 0o at which both the left- wound and right- wound spring should be attached so that

Elements Of Electromagnetics
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18-51. The uniform garage door has a mass of 150 kg and
is guided along smooth tracks at its ends. Lifting is done
using the two springs, each of which is attached to the
anchor bracket at A and to the counterbalance shaft at B
and C. As the door is raised, the springs begin to unwind
from the shaft, thereby assisting the lift. If each spring
provides a torsional moment of M = (0.70) N·m, where 0 is
in radians, determine the angle 0, at which both the left-
wound and right-wound spring should be attached so that
the door is completely balanced by the springs, i.e., when
the door is in the vertical position and is given a slight force
upward, the springs will lift the door along the side tracks to
the horizontal plane with no final angular velocity. Note:
The elastic potential energy of a torsional spring is
Ve =k0?, where M = k0 and in this case k = 0.7 N • m/rad.
A
В
3 m
4 m
Prob. 18–51
Transcribed Image Text:18-51. The uniform garage door has a mass of 150 kg and is guided along smooth tracks at its ends. Lifting is done using the two springs, each of which is attached to the anchor bracket at A and to the counterbalance shaft at B and C. As the door is raised, the springs begin to unwind from the shaft, thereby assisting the lift. If each spring provides a torsional moment of M = (0.70) N·m, where 0 is in radians, determine the angle 0, at which both the left- wound and right-wound spring should be attached so that the door is completely balanced by the springs, i.e., when the door is in the vertical position and is given a slight force upward, the springs will lift the door along the side tracks to the horizontal plane with no final angular velocity. Note: The elastic potential energy of a torsional spring is Ve =k0?, where M = k0 and in this case k = 0.7 N • m/rad. A В 3 m 4 m Prob. 18–51
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