177 Give the exact value of Cot

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Question:**

Give the exact value of \( \cot \left( \frac{17\pi}{6} \right) \).

**Explanation:**

This question asks for the exact value of the cotangent function evaluated at the angle \( \frac{17\pi}{6} \). To solve this, follow these steps:

1. Simplify the angle \( \frac{17\pi}{6} \):
   
   Since angles in trigonometry can be coterminal, \( \frac{17\pi}{6} \) can be reduced within one full circle (or \( 2\pi \)).

   \[
   \frac{17\pi}{6} = \frac{17}{6} \pi
   \]

   Subtract \( 2\pi \) (since one full circle is \( 2\pi \)):

   \[
   \frac{17}{6}\pi - 2\pi = \frac{17\pi - 12\pi}{6} = \frac{5\pi}{6}
   \]

   This means that \( \frac{17\pi}{6} \) is coterminal with \( \frac{5\pi}{6} \).

2. Evaluate \(\cot \left( \frac{5\pi}{6} \right) \):

   Cotangent is the reciprocal of tangent:

   \[
   \cot \theta = \frac{1}{\tan \theta}
   \]

   For \(\theta = \frac{5\pi}{6} \):

   \[
   \cot \left( \frac{5\pi}{6} \right) = \frac{1}{\tan \left( \frac{5\pi}{6} \right)}
   \]

   The tangent function of \( \frac{5\pi}{6} \) can be evaluated considering it is in the second quadrant:

   Tangent in the second quadrant: 
   
   \[
   \tan \left( \frac{5\pi}{6} \right) = - \tan \left( \pi - \frac{\pi}{6} \right) = - \tan \left( \frac{\pi}{6} \right) = - \frac{1}{\sqrt{3}}
   \]

   Hence:

   \[
   \cot \left(
Transcribed Image Text:**Question:** Give the exact value of \( \cot \left( \frac{17\pi}{6} \right) \). **Explanation:** This question asks for the exact value of the cotangent function evaluated at the angle \( \frac{17\pi}{6} \). To solve this, follow these steps: 1. Simplify the angle \( \frac{17\pi}{6} \): Since angles in trigonometry can be coterminal, \( \frac{17\pi}{6} \) can be reduced within one full circle (or \( 2\pi \)). \[ \frac{17\pi}{6} = \frac{17}{6} \pi \] Subtract \( 2\pi \) (since one full circle is \( 2\pi \)): \[ \frac{17}{6}\pi - 2\pi = \frac{17\pi - 12\pi}{6} = \frac{5\pi}{6} \] This means that \( \frac{17\pi}{6} \) is coterminal with \( \frac{5\pi}{6} \). 2. Evaluate \(\cot \left( \frac{5\pi}{6} \right) \): Cotangent is the reciprocal of tangent: \[ \cot \theta = \frac{1}{\tan \theta} \] For \(\theta = \frac{5\pi}{6} \): \[ \cot \left( \frac{5\pi}{6} \right) = \frac{1}{\tan \left( \frac{5\pi}{6} \right)} \] The tangent function of \( \frac{5\pi}{6} \) can be evaluated considering it is in the second quadrant: Tangent in the second quadrant: \[ \tan \left( \frac{5\pi}{6} \right) = - \tan \left( \pi - \frac{\pi}{6} \right) = - \tan \left( \frac{\pi}{6} \right) = - \frac{1}{\sqrt{3}} \] Hence: \[ \cot \left(
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