17.28 From each equation and standard enthalpy, predict whether the reaction willbe spontaneous at all temperatures, spontaneous at low temperatures butnonspontaneous at high temperatures, nonspontaneous at low temperatures butspontaneous at high temperatures, or not spontaneous at any temperature. Explainthe reasons.(a) 2HgO(s)2Hg(l) + O2(g)= 90.8 kJ→(b) 4Fe(s) + 302(g) → 2Fe2O3(s)AH = -1648.4 kJ(c) N2(g) + 3Cl2(g) → 2NC13(g)днө — 460 kJ作答(d) 2NH4NO3(s) →2N2(g) + 4H2O(g) + O2(g) AH® = -225.5 kJ

Solution : The chemical reactions can be classified into two types on the basis of…

17.28 From each equation and standard enthalpy, predict whether the reactior be spontaneous at all temperatures, spontaneous at low temperatures but nonspontaneous at high temperatures, nonspontaneous at low temperatures bi spontaneous at high temperatures, or not spontaneous at any temperature. Exj the reasons. (a) 2HgO(s) → 2Hg(1) + O2(g) AH® = 90.8 kJ (b) 4Fe(s) + 302(g) → 2Fe2O3(s) AH® = -1648.4 kJ

17.28 From each equation and standard enthalpy, predict whether the reactior be spontaneous at all temperatures, spontaneous at low temperatures but nonspontaneous at high temperatures, nonspontaneous at low temperatures bi spontaneous at high temperatures, or not spontaneous at any temperature. Exj the reasons. (a) 2HgO(s) → 2Hg(1) + O2(g) AH® = 90.8 kJ (b) 4Fe(s) + 302(g) → 2Fe2O3(s) AH® = -1648.4 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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