17. To obtain a certain shade of paint, Denise mixed 2 1/8 gallons of red paint with 1 1/4 gallons of black paint and 1 1/2 gallons of yellow paint. How much paint did he have?

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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17. To obtain a certain shade of paint, Denise mixed 2 1/8 gallons of red paint with 1 1/4 gallons of black paint and 1 1/2 gallons of yellow paint. How much paint did he have?

Expert Solution
Step 1

Given that to obtain a shade of a paint denise mixed 2 (1/8) gallons of red paint with 1 (1/14) gallons of black paint and 1 (1/12) gallons of yellow paint. 

Here different volumes of three paints are mixed to form a new paint. So we can say that the sum of  voumes of three paints is nothing but the volume of the new shade of paint.

Step 2

Here the volumes of paints are given as mixed fractions so we write them as proper fractions.

Volume of red paint = 2 (1/8) gallons = 17/8 gallons.

Volume of black paint = 1 (1/14) gallons = 15/14 gallons

Volume of yellow paint = 1 (1/2) gallons = 3/2 gallons.

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