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17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg. its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? a. 124 b. 60 c. 118 d. 54 e. 80

17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg. its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? a. 124 b. 60 c. 118 d. 54 e. 80

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Only 17 please exaplain me easy way step by step, formula sheet provided must use that please
The exam is closed book and closed notes. e. Not enough info Circular motion: a = Fast - ma; Weight: F=mg, ; g= 9.8 m/s'; Pavr= At 1 Kinetic energy: K =-m v²; Potential energy: U- mgy E = E E = U+K Rotational motion: 17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an 1 rev = 2n rad; - o'r; v= or; a =a r; a, = axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? O - Do + at; e = o t+ at?; 20a = o? - m, K= T-rx F; T=rFsing; a. 124 b. 60 Στ-Ια: c. 118 mR? I point mass- mr Idisk d. 54 e. 80 Ihoop = mR? Irodicenter) mL? Irodiend) = -mR? mR? Ihell- P dw dt I = Icom + MD? W Pavr = At work: W=t 0; W = Rolling: Veom = Ro K= T-f.R Famax = H,Fn Incline: F= mgsino F mgcos0 Angular momentum: Lpoint mass - m rxv L= mrvsin 0; L =m (r,v, - r,va)k L= lo m,x1 +m2x2 m, +m, miy1 +m2y2 m1 +m2 L = L I o =I 202 com = Y com =
Transcribed Image Text:The exam is closed book and closed notes. e. Not enough info Circular motion: a = Fast - ma; Weight: F=mg, ; g= 9.8 m/s'; Pavr= At 1 Kinetic energy: K =-m v²; Potential energy: U- mgy E = E E = U+K Rotational motion: 17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an 1 rev = 2n rad; - o'r; v= or; a =a r; a, = axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? O - Do + at; e = o t+ at?; 20a = o? - m, K= T-rx F; T=rFsing; a. 124 b. 60 Στ-Ια: c. 118 mR? I point mass- mr Idisk d. 54 e. 80 Ihoop = mR? Irodicenter) mL? Irodiend) = -mR? mR? Ihell- P dw dt I = Icom + MD? W Pavr = At work: W=t 0; W = Rolling: Veom = Ro K= T-f.R Famax = H,Fn Incline: F= mgsino F mgcos0 Angular momentum: Lpoint mass - m rxv L= mrvsin 0; L =m (r,v, - r,va)k L= lo m,x1 +m2x2 m, +m, miy1 +m2y2 m1 +m2 L = L I o =I 202 com = Y com =
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