17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg. its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? a. 124 b. 60 c. 118 d. 54 e. 80
17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg. its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the moment of inertia of the system (taking into account the ball's size)? a. 124 b. 60 c. 118 d. 54 e. 80
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Only 17 please exaplain me easy way step by step, formula sheet provided must use that please
Transcribed Image Text:The exam is closed book and closed notes.
e. Not enough info
Circular motion: a =
Fast - ma;
Weight: F=mg, ;
g= 9.8 m/s';
Pavr=
At
1
Kinetic energy: K =-m v²;
Potential energy: U- mgy
E = E
E = U+K
Rotational motion:
17. The surface of a solid ball is glued to one end of a rod and the rod is rotated about an
1 rev = 2n rad;
- o'r;
v= or;
a =a r;
a, =
axis through the other end of the rod and perpendicular to it. The ball's mass is 4.00 kg
its radius is 2.00 m. The rod's mass is 6.00 kg and its length is 3.00 m. What is the
moment of inertia of the system (taking into account the ball's size)?
O - Do + at;
e = o t+ at?;
20a = o? - m,
K=
T-rx F;
T=rFsing;
a. 124
b. 60
Στ-Ια:
c. 118
mR?
I point mass- mr
Idisk
d. 54
e. 80
Ihoop = mR?
Irodicenter)
mL?
Irodiend) =
-mR?
mR?
Ihell-
P dw
dt
I = Icom + MD?
W
Pavr =
At
work: W=t 0;
W =
Rolling:
Veom = Ro
K=
T-f.R
Famax = H,Fn
Incline: F= mgsino F mgcos0
Angular momentum:
Lpoint mass - m rxv
L= mrvsin 0;
L =m (r,v, - r,va)k
L= lo
m,x1 +m2x2
m, +m,
miy1 +m2y2
m1 +m2
L = L
I o =I 202
com =
Y com =
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