17. Draw the structure for the compound at the bottom of the page. Show your reasoning. C10H140 100 80 28 3000 2see 2000 156a 1000 9H 2H 2H 1H Í PPN TOC 1244 66ST 1514 C962 eszc
17. Draw the structure for the compound at the bottom of the page. Show your reasoning. C10H140 100 80 28 3000 2see 2000 156a 1000 9H 2H 2H 1H Í PPN TOC 1244 66ST 1514 C962 eszc
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:17. Draw the structure for the compound at the bottom of the page. Show your reasoning.
C10H140
100
88
68
40
20
4000
3500
3000
2500
2000
1508
1000
2H
2H
1H
Í PPN
3250
3826
2963
1514
66ST
1450
1381
1244
827
Expert Solution
Step 1
From the IR data,
IR = 827 cm-1
IR= set of IR pick around 1800-2000 cm-1
It is cleared that in the given compound, one benzene ring is present.
The Strong and brad IR absorption around 3250 cm-1 confirms the presence of O-H stretching.
And IR-absorption at 3028 cm-1 is due to the C=C-H stretching.
From the H-NMR data, four hydrogen atoms are attached to the ring and spite in doublet which conforms to the ortho and meta hydrogen atoms.
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