17. Calculate K, for the reaction 2NOCI(g)->2NO(g) + Cl2(g) at 400C if Ke at 400C for this reaction is 2.1 x 10-2. A. 2.1 x 10-2 B. 1.7 x 10-3 C. 0.70 D. 1.2 E. 3.8 x 104
17. Calculate K, for the reaction 2NOCI(g)->2NO(g) + Cl2(g) at 400C if Ke at 400C for this reaction is 2.1 x 10-2. A. 2.1 x 10-2 B. 1.7 x 10-3 C. 0.70 D. 1.2 E. 3.8 x 104
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:17. Calculate K, for the reaction 2NOCI(g)-> 2NO(g) + Cl2(g) at 400C if Kç at 400C for
this reaction is 2.1 x 10-2.
А. 2.1 x 10-2
B. 1.7 x 10-3
C. 0.70
D. 1.2
E. 3.8 x 104
18. On analysis, an equilibrium mixture for the reaction 2H2S(g)→ 2H2(g) + Sz(g) was
found to contain 1.0 mol H2S, 4.0 mol H2, and 0.80 mol S2 in a 4.0 L vessel. Calculate the
equilibrium constant, Kc, for this reaction.
A. 1.6
ou ba lom
В. 3.2
С. 12.8
bool videe etcoc
boot le 1oubong i
D. 0.64
E. 0.8
In obnotdo
19. 2.50 mol NOCI was placed in a 2.50 L reaction vessel at 400°C. After equilibrium was
established, it was found that 28% of the NOCI had dissociated according to the equation
2NOCI(g)–> 2NO(g) + Cl2(g).
Calculate the equilibrium constant, Ke, for the reaction.
A. 0.021
B. 0.039
C. 0.169
(p
D. 26
E. 47
20. 1.25 moles of NOCI were placed in a 2.50 L reaction chamber at 427°C. After equilibrium
was reached, 1.10 moles of NOCI remained. Calculate the equilibrium constant, Kẹ, for the
reaction 2NOCI(g) –> 2NO(g) + Cl(g); teq
А. 3.0 x 10-4
B. 1.8 x 103
C. 1.4 x 10-3
D. 5.6 x 10-4
E. 4.1 x 10-3
SCOCP SCHE
![Fe»Oa (e)d aruie correct equilibrium constant expression for the following reaction? tC
A. Ke = [Fe2O3] [H2]3 / [Fe]?[H2O]³
B. Kç = [H2] / [H2O]
C. Ke [H2O]³ / [H2]}
DK. = [Fe][H2O]} / [Fe2O3] [H2}³
E. Ke = [Fe] [H2O] / [Fe2O3] [H2]
14. A reaction with an equilibrium constant K, =1.5 x 10-25 would consist of which of the O X
following at equilibrium:
A. approximately equal reactants and products
B. some reactants and products with reactants slightly favored
C. some reactants and products with products slightly favored
D. essentially all reactants
E. essentially all products
lom0 b lom 02 lom 91 n or bnuo
eo dipo
CE G
803
15. The solubility of silver chloride can be increased by dissolving it in a solution containing
1oitA00 Issv no 0en booslq aw DO lom 02 er
bouol 20 ordaildat
ammonia.
AgCI (s) –> Ag* (aq) + Cl- (ag) K1 = 1.6 x 10-10
Ag* (aq) + 2NH3 (aq) –> Ag(NH3)2* (aq) K2 = 1.5 x 107
91 instenoo muindilups orit stoluoic
100.0 A
What is the value of the equilibrium constant for the overall reaction?
AgCl (s) + 2NH3 (aq) –> Ag(NH3)2* (aq) + CI (aq) Knet = ?
A. 1.5 x 107
B. 2.4 x 10-3
C. 3.1 x 10-3
D. 2.3 x 1014
E. 2.4 x 107 1oiA 1odmalo noas1102 beoolg oow 100A To 25lom 2
ooA n mundilupo sli olelule bontso DO1o 2olom 01 1 Lodoon
16. Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases,
phosgene and chlorine.
CCI4(g) + '½O2(g) –> COCI2(g) + Cl2(g), Kc = 4.4 x 10° at 1,000 K
Calculate Kc for the reaction 2CCI4(g) + O2(g) -> 2COC2(g) + 2C12(g).
A. 4.4 x 109
B. 8.8 x 109
C. 1.9 x 1010
D. 1.9 x 1019
E. 2.3 x 10-10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F315eb378-e0a1-4f42-b71f-bae7cf184c0a%2Ff3ec4244-b047-4059-8cd6-e228057e325b%2Fm0zea1o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Fe»Oa (e)d aruie correct equilibrium constant expression for the following reaction? tC
A. Ke = [Fe2O3] [H2]3 / [Fe]?[H2O]³
B. Kç = [H2] / [H2O]
C. Ke [H2O]³ / [H2]}
DK. = [Fe][H2O]} / [Fe2O3] [H2}³
E. Ke = [Fe] [H2O] / [Fe2O3] [H2]
14. A reaction with an equilibrium constant K, =1.5 x 10-25 would consist of which of the O X
following at equilibrium:
A. approximately equal reactants and products
B. some reactants and products with reactants slightly favored
C. some reactants and products with products slightly favored
D. essentially all reactants
E. essentially all products
lom0 b lom 02 lom 91 n or bnuo
eo dipo
CE G
803
15. The solubility of silver chloride can be increased by dissolving it in a solution containing
1oitA00 Issv no 0en booslq aw DO lom 02 er
bouol 20 ordaildat
ammonia.
AgCI (s) –> Ag* (aq) + Cl- (ag) K1 = 1.6 x 10-10
Ag* (aq) + 2NH3 (aq) –> Ag(NH3)2* (aq) K2 = 1.5 x 107
91 instenoo muindilups orit stoluoic
100.0 A
What is the value of the equilibrium constant for the overall reaction?
AgCl (s) + 2NH3 (aq) –> Ag(NH3)2* (aq) + CI (aq) Knet = ?
A. 1.5 x 107
B. 2.4 x 10-3
C. 3.1 x 10-3
D. 2.3 x 1014
E. 2.4 x 107 1oiA 1odmalo noas1102 beoolg oow 100A To 25lom 2
ooA n mundilupo sli olelule bontso DO1o 2olom 01 1 Lodoon
16. Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases,
phosgene and chlorine.
CCI4(g) + '½O2(g) –> COCI2(g) + Cl2(g), Kc = 4.4 x 10° at 1,000 K
Calculate Kc for the reaction 2CCI4(g) + O2(g) -> 2COC2(g) + 2C12(g).
A. 4.4 x 109
B. 8.8 x 109
C. 1.9 x 1010
D. 1.9 x 1019
E. 2.3 x 10-10
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