17. Applying the quotient rule, what is the correct FIRST STEP in finding the derivative of the given function? h(x) = x³-2x tan x D, (tan x) (x³ - 2x) - [D, (x² − 2x) (tan x)] (tan x)² D, (tan x) (x³) - [D, (x³) (tan x)] (tan x)² (x)= K'(x) = D, (x-2x) (tan x) - [D, (tan x) (x²-2x)] (tan x)² a
17. Applying the quotient rule, what is the correct FIRST STEP in finding the derivative of the given function? h(x) = x³-2x tan x D, (tan x) (x³ - 2x) - [D, (x² − 2x) (tan x)] (tan x)² D, (tan x) (x³) - [D, (x³) (tan x)] (tan x)² (x)= K'(x) = D, (x-2x) (tan x) - [D, (tan x) (x²-2x)] (tan x)² a
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![17. Applying the quotient rule, what is the correct FIRST STEP in finding
the derivative of the given function?
x³-2x
h(x) =
tan x
D, (tan x) (x³ - 2x) - [D. (x³ - 2x) (tanx)]
(tan x)²
D, (tan x) (x³) - [D. (x³) (tan x)]
(tan.x)²
h' (x) =
C
W'(x) =
a
Dx (x-2x) (tan x) - [D, (tanx) (x²-2x)]
(tan.x)²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9e22361-5be0-4bcf-97cc-6ff3602e2fdd%2F78b2029f-17c3-4b2d-bf39-9709d592f81b%2F46j3r9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:17. Applying the quotient rule, what is the correct FIRST STEP in finding
the derivative of the given function?
x³-2x
h(x) =
tan x
D, (tan x) (x³ - 2x) - [D. (x³ - 2x) (tanx)]
(tan x)²
D, (tan x) (x³) - [D. (x³) (tan x)]
(tan.x)²
h' (x) =
C
W'(x) =
a
Dx (x-2x) (tan x) - [D, (tanx) (x²-2x)]
(tan.x)²
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