17. A robot begins moving on a linear path at (3, 1). When it reaches (5,2), the robot turns 90° counterclockwise and continues to move linearly. After the turn, what is the y -coordinate of the robot's position when its x-coordinate is 4?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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### Problem Statement

17. A robot begins moving on a linear path at (3, 1). When it reaches (5, 2), the robot turns 90° counterclockwise and continues to move linearly. After the turn, what is the y-coordinate of the robot's position when its x-coordinate is 4? 

---

### Analysis

Let's break this down step by step:
1. **Initial Movement**:
   - The robot moves from point \( (3, 1) \) to point \( (5, 2) \).

2. **Direction of Initial Path**:
   - Calculate the slope of the path from \( (3, 1) \) to \( (5, 2) \):
     \[
     \text{slope} = \frac{2 - 1}{5 - 3} = \frac{1}{2}
     \]
   - The direction of this path is \( \frac{1}{2} \).

3. **90° Counterclockwise Turn**:
   - A 90° counterclockwise turn means the direction perpendicular to the original direction. The slope of the new path will be the negative reciprocal of the original slope:
     \[
     \text{new slope} = -\frac{1}{\left(\frac{1}{2}\right)} = -2
     \]

4. **Equation of New Path**:
   - We use the point-slope form of the line equation to find the equation of the new path through point \( (5, 2) \):
     \[
     y - 2 = -2(x - 5)
     \]
     Simplify the equation:
     \[
     y - 2 = -2x + 10
     \]
     \[
     y = -2x + 12
     \]

5. **Finding the y-coordinate when x = 4**:
   - Substitute \( x = 4 \) into the equation of the new path:
     \[
     y = -2(4) + 12
     \]
     \[
     y = -8 + 12
     \]
     \[
     y = 4
     \]

### Conclusion

The y-coordinate of the robot's position when its x-coordinate is 4 is \(\boxed{4}\).
Transcribed Image Text:### Problem Statement 17. A robot begins moving on a linear path at (3, 1). When it reaches (5, 2), the robot turns 90° counterclockwise and continues to move linearly. After the turn, what is the y-coordinate of the robot's position when its x-coordinate is 4? --- ### Analysis Let's break this down step by step: 1. **Initial Movement**: - The robot moves from point \( (3, 1) \) to point \( (5, 2) \). 2. **Direction of Initial Path**: - Calculate the slope of the path from \( (3, 1) \) to \( (5, 2) \): \[ \text{slope} = \frac{2 - 1}{5 - 3} = \frac{1}{2} \] - The direction of this path is \( \frac{1}{2} \). 3. **90° Counterclockwise Turn**: - A 90° counterclockwise turn means the direction perpendicular to the original direction. The slope of the new path will be the negative reciprocal of the original slope: \[ \text{new slope} = -\frac{1}{\left(\frac{1}{2}\right)} = -2 \] 4. **Equation of New Path**: - We use the point-slope form of the line equation to find the equation of the new path through point \( (5, 2) \): \[ y - 2 = -2(x - 5) \] Simplify the equation: \[ y - 2 = -2x + 10 \] \[ y = -2x + 12 \] 5. **Finding the y-coordinate when x = 4**: - Substitute \( x = 4 \) into the equation of the new path: \[ y = -2(4) + 12 \] \[ y = -8 + 12 \] \[ y = 4 \] ### Conclusion The y-coordinate of the robot's position when its x-coordinate is 4 is \(\boxed{4}\).
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