17) Assume that two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Which distribution is used to test the claim that women have a higher mean resting heart rate 17 than men? A) Normal B) t C) chi-square D) F

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Q: In some population the interquartile range of the values of income (x) represents 41,9% of its…

A: Formula Used: Median = L+n2-CFf×h Quartile deviation Q = Q3-Q12 First quartile Q1 = L + n4-CFf×h…

Q: A random sample of data has a mean of 75 and a variance of 25.a. Use Chebyshev’s theorem to…

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A:

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Q: A random sample of data has a mean of 78 and a variance of 49. a. Use Chebychev's theorem to…

A: The solution is shown below-

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A: Formula : sample variance :

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A:

Q: Compare the sample mean (3.25) for these drinking data to the population mean (µ = 3.00; σ = 0.75).…

A: The sample mean is given by 3.25.

Q: Calculate the statistical test value of Z

A: Given The data is as follows: H0: μ=95 vs H1:μ≠95 σ=3n=16x¯=90α=0.05

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A: The data is given as- Day Home Generator 1 123.4 124.7 2 123.6 124.1 3 124 124.6 4 123.6…

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A: Given thatsample size, n= 15sample mean, M= 20sample standard deviation, s=4population mean,

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A:

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A: Given data: Women Men 71 69 93 65 79 68 66 59 71 63 80 71 58 59 50 40 72 65…

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A: Given: n=5α=0.1

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A: Given that μ=157,σ=20 and n= 43 The mean of the sampling distribution of sample mean is,