168x+7,-6 ≤ x ≤ 14. Consider the function f(x) = 2x³ 9x² The absolute minimum of f(x) (on the given interval) is at X = and the absolute minimum of f(x) (on the given interval) is The absolute maximum of f(x) (on the given interval) is at X = and the absolute maximum of f(x) (on the given interval) is (Note: If a function has two x values at which a maxima or minima occur, enter them both separated by
168x+7,-6 ≤ x ≤ 14. Consider the function f(x) = 2x³ 9x² The absolute minimum of f(x) (on the given interval) is at X = and the absolute minimum of f(x) (on the given interval) is The absolute maximum of f(x) (on the given interval) is at X = and the absolute maximum of f(x) (on the given interval) is (Note: If a function has two x values at which a maxima or minima occur, enter them both separated by
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:**Consider the function** \( f(x) = 2x^3 - 9x^2 - 168x + 7 \), **for** \(-6 \leq x \leq 14\).
The absolute minimum of \( f(x) \) (on the given interval) is at
\( x = \_\_\_\_\_\_\_\_ \),
and the absolute minimum of \( f(x) \) (on the given interval) is
\(\_\_\_\_\_\_\_\_\).
The absolute maximum of \( f(x) \) (on the given interval) is at
\( x = \_\_\_\_\_\_\_\_ \),
and the absolute maximum of \( f(x) \) (on the given interval) is
\(\_\_\_\_\_\_\_\_\).
(Note: If a function has two x values at which a maxima or minima occur, enter them both separated by a comma.)
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