Answered: 168.3.0/23; 192.168.253.255/23; 192.16

Engineering

Computer Science

168.3.0/23; 192.168.253.255/23; 192.16

LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.

5th Edition

ISBN:9781337569798

Author:ECKERT

Publisher:ECKERT

Chapter12: Network Configuration

Section: Chapter Questions

Problem 16RQ

See similar textbooks

Similar questions

Note: Answer as Required only. X Q1) For the following network if A, B, C, D, E are the MAC addresses of the hosts, a,b,c,d,e are the IP addresses of the hosts: Host A LAN I Host B LAN 2 LAN3 LAN4 Host C Host D 192 1681.254/24 192.168.1.1\24 B1 12 12 12 3 1 2 1 2 A . A B2 B3 B4 B5 B B D D Complete B1,B2, B3, B4, B5 after following (Explain): (A-F I Mark each)(G 4 Marks) A) Wkst (PC) send frame (Packet) to Host B B) HOST B send frame (Packet ) to Wkst C) Host C send frame to Host A A D) Host D send frame to Host B E) Explain the benefits of using the bridges and the router in this network. F) Explain how the router know the Mac address of the IP Packet ? G) What is the maximum number of frame can user A send to B at a time? What if there is a loss of a frame? Explain the mechanism used to solve this problem.
Answer with handwriting ple
Question: Answer the following questions: The IP address is based on your student number SN as follow: The first byte is 198. The second byte is the 6th and 7th numbers of your SN, for example, if your SN is 438051221, the second byte is 12. The third byte is the 8th and 9th numbers of your SN, for example, if your SN is 438051221, the third byte is 21. • The forth byte is 0. 1. Consider a company which owns a license of this IP address. a. Write this IP address, for example 198.12.21.0 b. How many hosts at the maximum can be in this network? c. What are the first and the last addresses given to hosts? 2. The company likes to divide its network into 10 subnets. a. Determine the necessary number of bits borrowed. b. Determine the new subnet mask. c. Determine the maximum number of hosts in each subnet. d. Fill the following table Subnet Subnet First host Last host Broadcast address address address address 2 3 4 5 6. 7 8 9 10
Answer the following questions based on the concept of IPV6 Addressing Valid / If invalid, give your S# IPV6 Address Invalid comment а. 1200:0000:AB00:1234:0000:2552:7777:1313 b. ABCD:2673:ABCD:EFAB:1234:5678:9ABC:7362 с. 1200::AB00:1234::2552:7777:1313 d. FFFF:AAAA:BBBB:CCCC:DDDD:EEEE:FFFF:1111 Apply Only Rule 2 е. 1000:0001:0001:1000:0001:1000:0001:0000 f. 91CA:DED3:ABCO:2F8B:02AA:0CFF:FD28:9DDA Apply only Rule 1 g. FC00:0000:0000:0000:8E00:1275:0000:0084 h. 2000:0000:0000:0000:0000:ABCD:0000:0025
The given IPV6 subnet address is 2001:0DA7:FF00:FAF8: :/64. • Use the above IPV6 address for Subnet 0. • Increment the subnet field by 1 and find the IPV6 address for the remaining subnets. • Write simplified IPV6 address. Subnet IPV6 network address (Write simplified IPV6 address) Number 1 3. Complete the 2 following IPV6 addressing table 3 using IPV6 subnetting. Follow the instructions given below and write the IPV6 address in the table.
Answer the following questions: The IP address is based on your student number SN as follow: The first byte is 198. The second byte is the 6th and 7th numbers of your SN, for example, if your SN is 438051221, the second byte is The third byte is the 8th and 9th numbers of your SN, for example, if your SN is 438051221, the third byte is The forth byte is 0. Consider a company which owns a license of this IP address. Write this IP address, for example 198.12.21.0 How many hosts at the maximum can be in this network? What are the first and the last addresses given to hosts? The company likes to divide its network into 10 subnets. Determine the necessary number of bits borrowed. Determine the new subnet mask. Determine the maximum number of hosts in each subnet. Fill the following table Subnet Subnet address First host address Last host address Broadcast address 1…
Question 9 Convert the following IPv4 address into dot decimal address, and determine which type of these addresses are. a) 10000001 00001011 00001011 11101111 b) 11000001 10000011 00011011 11111111 c) 11100111 11011011 10001011 01101111 Computer network Full explain this question
Q10: Complete the frames (x & y) given below with appropriate port, IP and MAC addresses. The sender Host E has two applications running; one for email with port number 49254 and the other for accessing the web server with port number 52167. The frame x is intended for the BRACU Web server and frame y is coming from the Email Server. (MAC addresses are alphabets and IP addresses are numbers) [5] Port 80 Frame y K/93 BRACU G/51 Router BRACU Web ISP Frame x Server Router I/91 Port 25 Н 52 F/25 Hub-PT Hubo A/20 Switc-PT Switcho Swich-Pr Syitch1 Email Server J/92 B/21 E/24 C/22 D/23 Sender Frame X D. Mac S. MAC D. IP S. IP D. Port S. Port Data Trailer Frame Y D. Mac S. MAC D. IP S. IP D. Port S. Port Data Trailer ** *******END***: *** *** *****
You are given the network number of 86.30.88.0/20 with the following arrangement. (12 hosts) (30 hosts) You will need to create 4 subnets: Subnet A: 30 hosts Subnet B: 55 hosts Subnet C: 12 hosts Subnet D: 65 hosts (65 hosts) Z M (55 hosts) Finally, for each subnet created, you need to calculate and show: • The first, last and broadcast address • The subnet mask • Allocate IP numbers N
42, Which of the following statements about IPv6 are correct? A. IPv6 address 2001:0DB8:0000:0000:032A:0000:0000:2D70 can be abbreviated as 2001:DB8:0:0:32A::2D70. B. A link-local address (LLA) is a private IPv6 address that can be used only on the intranet. Because LLAS cannot be routed on the IPv6 public network, they cannot be used to directly access the public network. C. IPv6 addresses are classified into unicast, multicast, and broadcast addresses by IPv6 address prefix. D. IPv6 does not use ARP for address resolution. Instead, it uses ICMPv6 NS and NA packets to replace the address resolution function provided by ARP in IPv4.
Please help me explaining right answer of this question and please don’t use chegg to answer this question?
Please solve