16.792 g of Ba(OH)2 (171.342 g.mol) is weighed out and carefully dissolved to make a 500.00cm solutionA 25.00 cm³ of this solution is pipette then transferinto a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solutionlis then reacted with a 0.753 M solution of HNO3.Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H2O(1)The volume of the nitric acid that will be required to fully react with the base is:O 1.96 x 103 LO 5.21 x 103 LO 4.90 x 102 L1.96 x 10 L3.92 x 103 LO None of the above

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16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm solution A 25.00 cm' of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solutiorlis then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H20(1) The volume of the nitric acid that will be required to fully react with the base is: O 1.96 x 103 L O 5.21 x 103 L O 4.90 x 10-2 L 1.96 x 101 L 3.92 x 103 L O None of the above

16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm solution A 25.00 cm' of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solutiorlis then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H20(1) The volume of the nitric acid that will be required to fully react with the base is: O 1.96 x 103 L O 5.21 x 103 L O 4.90 x 10-2 L 1.96 x 101 L 3.92 x 103 L O None of the above

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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