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16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-3 gave the fol- 400 mmol dm-³ and [B]₁ lowing data (where c° = 1 mol/dm³): t/s 120 2.00 0 | | 0 0 |: + 0 104[C]/cº and a run with [A]o 0.400 mmol dm-³ and [B]₁ -3 mmol dm-3 gave 10-³t/s 240 3.00 69 2.00 360 3.50 485 104[C]/cº 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 208 3.00 4.00 = 1000

16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-3 gave the fol- 400 mmol dm-³ and [B]₁ lowing data (where c° = 1 mol/dm³): t/s 120 2.00 0 | | 0 0 |: + 0 104[C]/cº and a run with [A]o 0.400 mmol dm-³ and [B]₁ -3 mmol dm-3 gave 10-³t/s 240 3.00 69 2.00 360 3.50 485 104[C]/cº 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 208 3.00 4.00 = 1000

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-³ gave the fol- 400 mmol dm ³ and [B] lowing data (where cº = 1 mol/dm³): t/s 0 120 0 2.00 0.400 mmol dm-³ and [B]₁ 0 0 240 3.00 = 104[C]/cº and a run with [A]o mmol dm-³ gave 10-³t/s 69 485 104[C]/cº 2.00 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 360 3.50 208 3.00 ∞ 4.00 = 1000 ∞
Transcribed Image Text:16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-³ gave the fol- 400 mmol dm ³ and [B] lowing data (where cº = 1 mol/dm³): t/s 0 120 0 2.00 0.400 mmol dm-³ and [B]₁ 0 0 240 3.00 = 104[C]/cº and a run with [A]o mmol dm-³ gave 10-³t/s 69 485 104[C]/cº 2.00 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 360 3.50 208 3.00 ∞ 4.00 = 1000 ∞
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