16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-3 gave the fol- 400 mmol dm-³ and [B]₁ lowing data (where c° = 1 mol/dm³): t/s 120 2.00 0 | | 0 0 |: + 0 104[C]/cº and a run with [A]o 0.400 mmol dm-³ and [B]₁ -3 mmol dm-3 gave 10-³t/s 240 3.00 69 2.00 360 3.50 485 104[C]/cº 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 208 3.00 4.00 = 1000
16.34 For the reaction A + B → C + D, a run with [A]o = 0.400 mmol dm-3 gave the fol- 400 mmol dm-³ and [B]₁ lowing data (where c° = 1 mol/dm³): t/s 120 2.00 0 | | 0 0 |: + 0 104[C]/cº and a run with [A]o 0.400 mmol dm-³ and [B]₁ -3 mmol dm-3 gave 10-³t/s 240 3.00 69 2.00 360 3.50 485 104[C]/cº 3.50 4.00 Find the rate law and the rate constant. The numbers have been chosen to make determination of the orders simple. 208 3.00 4.00 = 1000
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![16.34 For the reaction A + B → C + D, a run with [A]o
=
0.400 mmol dm-³ gave the fol-
400 mmol dm ³ and [B]
lowing data (where cº = 1 mol/dm³):
t/s
0
120
0
2.00
0.400 mmol dm-³ and [B]₁
0
0
240
3.00
=
104[C]/cº
and a run with [A]o
mmol dm-³ gave
10-³t/s
69
485
104[C]/cº
2.00
3.50
4.00
Find the rate law and the rate constant. The numbers have been
chosen to make determination of the orders simple.
360
3.50
208
3.00
∞
4.00
= 1000
∞](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4ac7ae7-e4f9-47c1-b266-8dda39f5db38%2F82e32909-8f91-45d1-b688-9e5c73cdab8b%2F5pkkjst_processed.png&w=3840&q=75)
Transcribed Image Text:16.34 For the reaction A + B → C + D, a run with [A]o
=
0.400 mmol dm-³ gave the fol-
400 mmol dm ³ and [B]
lowing data (where cº = 1 mol/dm³):
t/s
0
120
0
2.00
0.400 mmol dm-³ and [B]₁
0
0
240
3.00
=
104[C]/cº
and a run with [A]o
mmol dm-³ gave
10-³t/s
69
485
104[C]/cº
2.00
3.50
4.00
Find the rate law and the rate constant. The numbers have been
chosen to make determination of the orders simple.
360
3.50
208
3.00
∞
4.00
= 1000
∞
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