16. When n is small (less than 30), how does the shape of the t distribution compare to the normal distribution? a. It is almost perfectly normal. It is flatter and more spread out than the normal b. distribution. It is taller and narrower than the normal С. distribution. There is no consistent relationship between the t d. distribution and the normal distribution.

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**Question 16:** When \( n \) is small (less than 30), how does the shape of the t distribution compare to the normal distribution?

a. It is almost perfectly normal.

b. It is flatter and more spread out than the normal distribution.

c. It is taller and narrower than the normal distribution.

d. There is no consistent relationship between the t distribution and the normal distribution.
Transcribed Image Text:**Question 16:** When \( n \) is small (less than 30), how does the shape of the t distribution compare to the normal distribution? a. It is almost perfectly normal. b. It is flatter and more spread out than the normal distribution. c. It is taller and narrower than the normal distribution. d. There is no consistent relationship between the t distribution and the normal distribution.
**Question 15**

A researcher conducts a hypothesis test using a sample of \( n = 20 \) from an unknown population. What is the \( df \) (degrees of freedom) value for the t statistic?

a. 19

b. 20

c. 21

d. Cannot be determined from the information given

**Explanation:**

When conducting a t-test, the degrees of freedom (df) is typically calculated as the sample size minus one (\( n - 1 \)). Therefore, if the sample size \( n \) is 20, then the degrees of freedom would be \( 20 - 1 = 19 \). Hence, the correct answer is option a.
Transcribed Image Text:**Question 15** A researcher conducts a hypothesis test using a sample of \( n = 20 \) from an unknown population. What is the \( df \) (degrees of freedom) value for the t statistic? a. 19 b. 20 c. 21 d. Cannot be determined from the information given **Explanation:** When conducting a t-test, the degrees of freedom (df) is typically calculated as the sample size minus one (\( n - 1 \)). Therefore, if the sample size \( n \) is 20, then the degrees of freedom would be \( 20 - 1 = 19 \). Hence, the correct answer is option a.
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