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16. Using the answer for question 14, and given a cart mass of M = 3.0 kg, the tension in the cable (N) is: M +x m +x O 7.35 O 2.45 O 4.90 9.80 O 0.613 0.817 O 3.267 O 1.633

16. Using the answer for question 14, and given a cart mass of M = 3.0 kg, the tension in the cable (N) is: M +x m +x O 7.35 O 2.45 O 4.90 9.80 O 0.613 0.817 O 3.267 O 1.633

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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16. Using the answer for question 14, and given a cart mass of M = 3.0 kg, the tension in the cable (N) is: +X m +X O 7.35 O 2.45 O 4.90 O 9.80 O 0.613 0.817 O 3.267 O 1.633
Transcribed Image Text:16. Using the answer for question 14, and given a cart mass of M = 3.0 kg, the tension in the cable (N) is: +X m +X O 7.35 O 2.45 O 4.90 O 9.80 O 0.613 0.817 O 3.267 O 1.633
14. The measured velocity (m/s) of either masses of the modified Atwood's machine for various times is given in the below table. Using Excel to graph the data, and based on the slope of velocity vs. time graph, the measured acceleration (m/s2) of either masses is: +x m +X t(sec) v(m/s) 0.5 1.23 1 2.49 |1.5 3.65 2 |4.85 2.5 6.13 3 7.38 O 2.45 O 0.0013
Transcribed Image Text:14. The measured velocity (m/s) of either masses of the modified Atwood's machine for various times is given in the below table. Using Excel to graph the data, and based on the slope of velocity vs. time graph, the measured acceleration (m/s2) of either masses is: +x m +X t(sec) v(m/s) 0.5 1.23 1 2.49 |1.5 3.65 2 |4.85 2.5 6.13 3 7.38 O 2.45 O 0.0013
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