16. S cot xdx /1 + In sin x

Q: 5. (tan2x + cot2x)² dx

A:

Q: 5. Simplify. tanx (cscx - sin x)

A: The given expression is tanxcscx-sinx. We have to simplify the given expression. Here we use the…

Q: Differentiate sin x +1

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Q: 2. sin 2x 1 - sin² x = 2 tan x

A: Aim: To show that sin(2x)1-sin2(x)=2tan(x)

Q: find x for which = 0. dx

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Q: -1 L tsin(2t) 4

A: Given function is  Let f(t)= 1/4 tsin(2t)

Q: csc 2x - cot 2x = 1

A:

Q: Differentiate Sin (m sin-1 x)

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Q: BIN 2 sin² x cos x dx

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Q: Show that Cosx dx 9- Sin 3D

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Q: What vaule of 0 = sin (0/3 - 10)

A: that is equal to 0=sin(0-10) than 0=sin(-10) such that -10=sin^-1(0) that is equal to zero

Q: COs 2x cotx x – tanx %3D sinx · cOsx

A:

Q: Find sec2x if sin x = 6/10 and sec x < 0

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Q: sečxdx ztanx 5-9tarix ansi sin 2

A: Solution is done in step 2

Q: Evaluate sin2xlogtanx dx

A: Given:  Let I=∫0π2 sin2xlogtan x dx To Find: To evaluate the given integral.

Q: Tanb =-2/5 & sinb<0

A:

Q: L{ sin 2t sin 3t}

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Q: Lim Sin 2x Sin 2x |- CoS1ox

A: Given: L=limx→0sin2x1-cos10x+sin2x2x