16 V 40 a 4 V- =12 V 30 20 120 E3 V b. 103 -6 V 16 2 V= 20 7v c 27 V 3 V

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Using series and parallel of batteries and potential difference, solve:

(a) I1, I2, I3, I4, I5, I6
(b) Vab, Vdc, Vca, Vbd

16 V
a
40
12 V
30
4 V.
120
20
=3 V
d.
A9
16
2 V=
50
20
27 V
3 V
7 v c
Transcribed Image Text:16 V a 40 12 V 30 4 V. 120 20 =3 V d. A9 16 2 V= 50 20 27 V 3 V 7 v c
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