Homework Help is Here – Start Your Trial Now!
Science
Physics
16° to the horizontal. Its initial A block is sliding down a ramp at an angle of speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, uk, between the block and the ramp? Ө

16° to the horizontal. Its initial A block is sliding down a ramp at an angle of speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, uk, between the block and the ramp? Ө

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
Topic Video
Question

Please help did I completed this question corre

A block is sliding down a ramp at an angle of 0 = 16° to the horizontal. Its initial speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, µ., between the block and the ramp? Ө
Transcribed Image Text:A block is sliding down a ramp at an angle of 0 = 16° to the horizontal. Its initial speed is 2.8 m/s. After sliding 13.6 m along the ramp, it comes to a rest. What is the coefficient of kinetic friction, µ., between the block and the ramp? Ө
imgsing-5 " " " f= = = ma =D₂ 0 = (2₁8nd1/²³ - 2x4x1333 13.6m a = 7.84 m/s 2 2 = vi ²-2 as 2x 13.6m = 0.29 m/ = 2.41M15 acceleration perpendicular to the ram And there is no : N₂ my cos & mg sine - lin N = ma mg my sin 6 Мкт MK mg cost = ma gsine - Ming cost = 9 мнд Given 0 = 16 9.8 m/s ² x sin 16° 2 x sin 16° - MK x 9.8 m/s ² x cos 16° = 0.29 m/s ² 2.7 mis- 0.29mis" un x 9.42 UK мк = UK 9.4241=√10. 256.
Transcribed Image Text:imgsing-5 " " " f= = = ma =D₂ 0 = (2₁8nd1/²³ - 2x4x1333 13.6m a = 7.84 m/s 2 2 = vi ²-2 as 2x 13.6m = 0.29 m/ = 2.41M15 acceleration perpendicular to the ram And there is no : N₂ my cos & mg sine - lin N = ma mg my sin 6 Мкт MK mg cost = ma gsine - Ming cost = 9 мнд Given 0 = 16 9.8 m/s ² x sin 16° 2 x sin 16° - MK x 9.8 m/s ² x cos 16° = 0.29 m/s ² 2.7 mis- 0.29mis" un x 9.42 UK мк = UK 9.4241=√10. 256.
Expert Solution
steps

Step by step

Solved in 4 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Second law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS