**Problem 16:**Given the equation \( \sin \theta = 0.5035 \), find the value of the positive acute angle \( \theta \) to the nearest minute.*Solution:*To solve for \( \theta \), use the inverse sine function:\[ \theta = \sin^{-1}(0.5035) \]Using a calculator to find the inverse sine:\[ \theta \approx 30.1284^\circ \]Convert the decimal part of the degree to minutes:1. Take the decimal part \(0.1284\).2. Multiply by 60 (since 1 degree = 60 minutes):\[ 0.1284 \times 60 \approx 7.704 \]Since we need the angle to the nearest minute, we round 7.704 to 8.So, the value of the positive acute angle \( \theta \) to the nearest minute is:\[ \theta \approx 30^\circ 8' \]

Name: **Problem 16:**Given the equation \( \sin \theta = 0.5035 \), find th
Uploaded: 2024-03-20T06:46:55.000Z
Channel: Bartleby
Description: **Problem 16:**Given the equation \( \sin \theta = 0.5035 \), find the value of the positive acute angle \( \theta \) to the nearest minute.*Solution:*To solve for \( \theta \), use the inverse sine function:\[ \theta = \sin^{-1}(0.5035) \]Using a c