16) Center at (-6, 9) Vertex at (–18, 9) 5 Eccentricity = - 4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Use the information provided to write the standard form equation of each hyperbola.
9) Vertices: (1 + 3 Vī15, –7), (1 – 3 V15, -7)
Endpoints of Conjugate Axis: (1, -7 + 5V5)
(1, -7 – 5V5)
10) Vertices: (19, 2), (1, 2)
Foci: (10 + V130, 2), (10 – V130, 2)
11) Vertices: (-10, 1). (–10, –17)
Perimeter of Central Rectangle = 76
12) Vertices: (7, -2), (5, –2)
Asymptotes: y = 11x – 68
y =-11x + 64
14) Foci: (6, 1 + 2V58), (6, 1 – 2 V58)
13) Center at (10, –4)
Transverse axis is vertical and 18 units long
Conjugate axis is 10 units long
Points on the hyperbola are 28 units closer
to one focus than the other
16) Center at (-6, 9)
Vertex at (-18, 9)
15)
5
Eccentricity
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb90438f-eabc-4035-a2d1-5c73da14abd9%2F4eec69f8-4ef8-46e1-a05e-fac2544bd8dc%2Fflzjsah_processed.png&w=3840&q=75)
Transcribed Image Text:Use the information provided to write the standard form equation of each hyperbola.
9) Vertices: (1 + 3 Vī15, –7), (1 – 3 V15, -7)
Endpoints of Conjugate Axis: (1, -7 + 5V5)
(1, -7 – 5V5)
10) Vertices: (19, 2), (1, 2)
Foci: (10 + V130, 2), (10 – V130, 2)
11) Vertices: (-10, 1). (–10, –17)
Perimeter of Central Rectangle = 76
12) Vertices: (7, -2), (5, –2)
Asymptotes: y = 11x – 68
y =-11x + 64
14) Foci: (6, 1 + 2V58), (6, 1 – 2 V58)
13) Center at (10, –4)
Transverse axis is vertical and 18 units long
Conjugate axis is 10 units long
Points on the hyperbola are 28 units closer
to one focus than the other
16) Center at (-6, 9)
Vertex at (-18, 9)
15)
5
Eccentricity
4
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