16- Aluminum Al in a 3.533 g soil sample was determined by precipitating as Al₂O₁ (102.0 g/mol). precipitate was 0.0435 g. calculate the mass percent of Al (27.0 g/mol) in the sample. a) 0.65% b) 3.66% c) 27.1% d) 1.07% e) 14.5% 17-Consider the following titration curve that corresponds to the titration of a weak acid with a strong base. From the data shown, what is the approximate Ka of the acid? a) 1x10-12 b) 1x107 c) 1x108 d) 1x10 e) 1x10⁹ Hd 12 10 8 6 ON 2 0 100 200 300 Volume of titrant, ml. 400

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Chapter1: Chemical Foundations
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Aluminum Al in a boxed 3.533g soil sample was determined by precipitating as A*l_{2}*O_{3} (102g / m * of the The mass of precipitate was 0.0435 g. calculate the mass percent of Al (27g / m * ol) in the sample.

16- Aluminum Al in a 3.533 g soil sample was determined by precipitating as Al2O (102.0 g/mol). The mass of the
precipitate was 0.0435 g. calculate the mass percent of Al (27.0 g/mol) in the sample.
a) 0.65%
b) 3.66%
c) 27.1%
d) 1.07%
e) 14.5%
17- Consider the following titration curve that corresponds to the titration
of a weak acid with a strong base. From the data shown, what is the
approximate Ka of the acid?
a) 1x10-¹2
b) 1x107
c) 1x10-8
d) 1x10-s
e) 1x10⁹
Hd
14
12
ON SON
10
0
200
300
100
Volume of titrant, ml.
400
Transcribed Image Text:16- Aluminum Al in a 3.533 g soil sample was determined by precipitating as Al2O (102.0 g/mol). The mass of the precipitate was 0.0435 g. calculate the mass percent of Al (27.0 g/mol) in the sample. a) 0.65% b) 3.66% c) 27.1% d) 1.07% e) 14.5% 17- Consider the following titration curve that corresponds to the titration of a weak acid with a strong base. From the data shown, what is the approximate Ka of the acid? a) 1x10-¹2 b) 1x107 c) 1x10-8 d) 1x10-s e) 1x10⁹ Hd 14 12 ON SON 10 0 200 300 100 Volume of titrant, ml. 400
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