16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the following: I. value of summation and direction of Vx II. value of summation and direction of Vy and III. The value of resultant vector of velocity and the angle formed A. 262.66 m/s West ; 156.03 m/s North ; 305.51 m/s, 30.71 N of W B. 245.45 m/s North ; 145.02 m/s West ; 385.09 m/s, 39.09 W of N C. 156.23 m/s West ; 58.74 m/s North ; 166.91 m/s, 28.54 N of W D. 178.34 m/s North ; 65.36 m/s West ; 189.94 m/s, 19.34 W of N
16-20 A motorcyclist heads 267 m/s, 35.76° N of W and then it changes its direction heading 46 m/s West before it reaches its destination. Calculate the following:
I. value of summation and direction of Vx
II. value of summation and direction of Vy and
III. The value of resultant vector of velocity and the angle formed
A. 262.66 m/s West ; 156.03 m/s North ; 305.51 m/s, 30.71 N of W
B. 245.45 m/s North ; 145.02 m/s West ; 385.09 m/s, 39.09 W of N
C. 156.23 m/s West ; 58.74 m/s North ; 166.91 m/s, 28.54 N of W
D. 178.34 m/s North ; 65.36 m/s West ; 189.94 m/s, 19.34 W of N
21-25 A body is projected with an initial velocity of 25.5 m/s at 30 below the horizontal. Find:
I. time of flight
II. the maximum height attained by the body
III. range
A. Time of flight = 1.3s ; Maximum height = 7.7m ; Range = 55m
B. Time of flight = 2.5s ; Maximum height = 8.7m ; Range = 60m
C. Time of flight = 1.1s ; Maximum height = 6.9m ; Range = 45m
D. Time of flight = 2.3s ; Maximum height = 9.7m ; Range = 65m

Step by step
Solved in 4 steps with 4 images









