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158% This parabola would have a general equation: g(x) = ax? + bx +c for some value a, b, c. Do hot find these values. (c) To find that area we could find the integral of the parabola between -2 < x< 2 Show: 16 dx =-a + 4c (d) Through trial and error, Simpson found that the expression below evaluates to the same expression in terms of a, b and c. Confirm this by substitution: h (g(-2) + 4g(0) + g(2)) where h is the width between the function values.

158% This parabola would have a general equation: g(x) = ax? + bx +c for some value a, b, c. Do hot find these values. (c) To find that area we could find the integral of the parabola between -2 < x< 2 Show: 16 dx =-a + 4c (d) Through trial and error, Simpson found that the expression below evaluates to the same expression in terms of a, b and c. Confirm this by substitution: h (g(-2) + 4g(0) + g(2)) where h is the width between the function values.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2 17 > 158% ab This parabola would have a general equation: g(x) = ax2 + bx + c for some value a, b, c. Do hot find these values. (c) To find that area we could find the integral of the parabola between-2 < x < 2 Show: 16 g(x) dx = a + 4c (d) Through trial and error, Simpson found that the expression below evaluates to the same expression in terms of a, b and c. Confirm this by substitution: (g(-2) + 4g(0) + g(2)) where h is the width between the function values.
Transcribed Image Text:2 17 > 158% ab This parabola would have a general equation: g(x) = ax2 + bx + c for some value a, b, c. Do hot find these values. (c) To find that area we could find the integral of the parabola between-2 < x < 2 Show: 16 g(x) dx = a + 4c (d) Through trial and error, Simpson found that the expression below evaluates to the same expression in terms of a, b and c. Confirm this by substitution: (g(-2) + 4g(0) + g(2)) where h is the width between the function values.
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