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152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V

152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V
Transcribed Image Text:152-240° V C a n 1520° V ial -8+j8 N Vab in 152-120° V Vca b ibl 1 Vbc icl -8+j80-8+j8 N Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial ibl ici = = = 0 A ° A L ° A Vab Ubc =1 = Vca = ° V V ° V
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