15.lf the second derivative of f is given by f"(x) = x(x+3)(2 – x)² , then the graph of f has inflection points at which x values? (A)x = -3 only (D) x = 0 and x = 2 (B) x = 0 only (E) x = -3 and x = 0 (C)x = 2 only

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question 15**: If the second derivative of \( f \) is given by \( f''(x) = x(x + 3)(2 - x)^2 \), then the graph of \( f \) has inflection points at which \( x \) values?

**Options:**

- (A) \( x = -3 \) only
- (B) \( x = 0 \) only
- (C) \( x = 2 \) only
- (D) \( x = 0 \) and \( x = 2 \)
- (E) \( x = -3 \) and \( x = 0 \)

**Explanation of Concepts:**

An inflection point occurs where the concavity of the function changes, which is found by analyzing the second derivative \( f''(x) \). Specifically, potential inflection points occur where \( f''(x) = 0 \) or where \( f''(x) \) is undefined. At these points, the sign of \( f''(x) \) must change. In this case, \( f''(x) \) is set to zero to find potential inflection points.
Transcribed Image Text:**Question 15**: If the second derivative of \( f \) is given by \( f''(x) = x(x + 3)(2 - x)^2 \), then the graph of \( f \) has inflection points at which \( x \) values? **Options:** - (A) \( x = -3 \) only - (B) \( x = 0 \) only - (C) \( x = 2 \) only - (D) \( x = 0 \) and \( x = 2 \) - (E) \( x = -3 \) and \( x = 0 \) **Explanation of Concepts:** An inflection point occurs where the concavity of the function changes, which is found by analyzing the second derivative \( f''(x) \). Specifically, potential inflection points occur where \( f''(x) = 0 \) or where \( f''(x) \) is undefined. At these points, the sign of \( f''(x) \) must change. In this case, \( f''(x) \) is set to zero to find potential inflection points.
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