15. Use the graph below of f(x) = x² - 4 to answer the following questions: evica varit bns anodsups to matave i ol philise auor & lool norli br eril to beega erll bris teiswlllla a. Find the y intercepts b. Find f(0) -8 -4 8 4 O -8- 4 -00 8
15. Use the graph below of f(x) = x² - 4 to answer the following questions: evica varit bns anodsups to matave i ol philise auor & lool norli br eril to beega erll bris teiswlllla a. Find the y intercepts b. Find f(0) -8 -4 8 4 O -8- 4 -00 8
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![The image contains a math question related to the function \( f(x) = x^2 - 4 \). Below is a summary and explanation of the content, suitable for an educational website:
### Problem Statement
**15. Use the graph below of \( f(x) = x^2 - 4 \) to answer the following questions:**
The graph provided represents the quadratic function \( f(x) = x^2 - 4 \). This is a standard parabola opening upwards, with its vertex located at the point (0, -4).
### Graph Description
- **Axes:** The graph is plotted on a coordinate plane with both x- and y-axes marked with intervals of 2 units.
- **Parabola:** The parabola intersects the x-axis at two points, which are the roots of the equation \( x^2 - 4 = 0 \). These roots are x = -2 and x = 2.
- **Vertex:** The vertex of the parabola is at (0, -4), indicating the minimum point of the function.
- **Symmetry:** The graph is symmetric about the y-axis.
### Questions
a. **Find the y-intercepts.**
b. **Find \( f(0) \).**
### Solutions
a. The y-intercept occurs where the graph intersects the y-axis (where \( x = 0 \)). From the graph, this is at the point (0, -4).
b. To find \( f(0) \), substitute \( x = 0 \) into the function:
\[ f(0) = 0^2 - 4 = -4 \]
Thus, the y-intercept is at the point (0, -4), and \( f(0) = -4 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39f8eda8-4420-4bda-ab27-1b53a7c9ec36%2F3dfc504f-7810-427f-9f32-175f61e4c5b8%2Fhkn4w6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image contains a math question related to the function \( f(x) = x^2 - 4 \). Below is a summary and explanation of the content, suitable for an educational website:
### Problem Statement
**15. Use the graph below of \( f(x) = x^2 - 4 \) to answer the following questions:**
The graph provided represents the quadratic function \( f(x) = x^2 - 4 \). This is a standard parabola opening upwards, with its vertex located at the point (0, -4).
### Graph Description
- **Axes:** The graph is plotted on a coordinate plane with both x- and y-axes marked with intervals of 2 units.
- **Parabola:** The parabola intersects the x-axis at two points, which are the roots of the equation \( x^2 - 4 = 0 \). These roots are x = -2 and x = 2.
- **Vertex:** The vertex of the parabola is at (0, -4), indicating the minimum point of the function.
- **Symmetry:** The graph is symmetric about the y-axis.
### Questions
a. **Find the y-intercepts.**
b. **Find \( f(0) \).**
### Solutions
a. The y-intercept occurs where the graph intersects the y-axis (where \( x = 0 \)). From the graph, this is at the point (0, -4).
b. To find \( f(0) \), substitute \( x = 0 \) into the function:
\[ f(0) = 0^2 - 4 = -4 \]
Thus, the y-intercept is at the point (0, -4), and \( f(0) = -4 \).

Transcribed Image Text:c. Find the x-intercepts
(-1, 0)
d. What is the domain?
e. What is the range?
Expert Solution
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