15. in your treatment, compare the computed F ccmputed (Fc) value from that of Tabular value (5% and 1%), then answer the following questions: a. is the value of Computed Fc is greater than the tabular value in both 5% and 1%? (yes or no). b. is there is any significant differences among the treatment means? (yes or no). C. what is the CV value?

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13. Using this ANOVA Table (CRD) and enter all your computed values. (green)
F-Value
Tabular
1%
SV
df
Computed
(Fc)
SS
MS
5%
Treatment
Experimental Error
Total
14. Using point of distribution of F- table and the df of this table, locate the tabular value of 5%
and 1% and reflect it in your Table (5% and 1%). (Blue)
15. in your treatment, compare the computed F ccmputed (Fc) value from that of Tabular value (5% and
1%), then answer the following questions:
a. is the value of Computed Fc is greater than the tabular value in both 5% and 1%?
(yes or no).
b. is there is any significant differences among the treatment means? (yes or no)
C. what is the CV value?
Áctivity No. 2. Using the RCBD, compute the ANCVA of the following data in this table 2.
Table 2. weight of sorghum (t'ha) as affected different organic-based enhancers.
Organic-based
enhancers
I
II
II
IV
Total
Mean
T1 -FPJ
2.1
2.5
3.2
3.6
T2 – FAA
4.0
3.9
4.3
4.5
4.9
5.1
5.5
6.1
T3 - Vermi Tea
T4- FOBF
Total
2.9
3.1
3.2
4.4
Mean/Grand Mean
Note: see to it first to compute the treatment total and the mean block total and its mean as well the grand
total and grand mean. Write directly your answer/s in Table 2 (blank). Then please proceed to actual
computation following the Gomez and Gomez or Gregorio's procedure.
Transcribed Image Text:13. Using this ANOVA Table (CRD) and enter all your computed values. (green) F-Value Tabular 1% SV df Computed (Fc) SS MS 5% Treatment Experimental Error Total 14. Using point of distribution of F- table and the df of this table, locate the tabular value of 5% and 1% and reflect it in your Table (5% and 1%). (Blue) 15. in your treatment, compare the computed F ccmputed (Fc) value from that of Tabular value (5% and 1%), then answer the following questions: a. is the value of Computed Fc is greater than the tabular value in both 5% and 1%? (yes or no). b. is there is any significant differences among the treatment means? (yes or no) C. what is the CV value? Áctivity No. 2. Using the RCBD, compute the ANCVA of the following data in this table 2. Table 2. weight of sorghum (t'ha) as affected different organic-based enhancers. Organic-based enhancers I II II IV Total Mean T1 -FPJ 2.1 2.5 3.2 3.6 T2 – FAA 4.0 3.9 4.3 4.5 4.9 5.1 5.5 6.1 T3 - Vermi Tea T4- FOBF Total 2.9 3.1 3.2 4.4 Mean/Grand Mean Note: see to it first to compute the treatment total and the mean block total and its mean as well the grand total and grand mean. Write directly your answer/s in Table 2 (blank). Then please proceed to actual computation following the Gomez and Gomez or Gregorio's procedure.
Anova: Single Factor
SUMMARY
Sum Average
3 8.45 2.816666667 0.969733333
2 5.25
Groups
Count
Variance
T1
T2
T3
2.625
0.00125
3 7.39 2.463333333 0.220133333
3 6.96
3 9.99
T4
2.32
0.3316
T5
3.33
0.6076
ANOVA
Source of Variation
Treatment
Experimental Error 4.259383333
SS
df
MS
P-value
F-value 5% F-value 1%
1.839902381
4 0.459975595 0.971920119 0.468543524 3.633088511 6.42208546|
9 0.473264815
Total
| 6.099285714 13
14.
From the table 1,
Number of treatment groups is 5 and the number of blocks is
3.
Treatment df, taf=5-1=4
Error df, Edf-5(3-1)=10
Level of significance is 1%.
From the F distribution table, the F tabulated value
corresponding with 0.01 level, 4 as treatment df and 10 as
error df is 5.9943.
Transcribed Image Text:Anova: Single Factor SUMMARY Sum Average 3 8.45 2.816666667 0.969733333 2 5.25 Groups Count Variance T1 T2 T3 2.625 0.00125 3 7.39 2.463333333 0.220133333 3 6.96 3 9.99 T4 2.32 0.3316 T5 3.33 0.6076 ANOVA Source of Variation Treatment Experimental Error 4.259383333 SS df MS P-value F-value 5% F-value 1% 1.839902381 4 0.459975595 0.971920119 0.468543524 3.633088511 6.42208546| 9 0.473264815 Total | 6.099285714 13 14. From the table 1, Number of treatment groups is 5 and the number of blocks is 3. Treatment df, taf=5-1=4 Error df, Edf-5(3-1)=10 Level of significance is 1%. From the F distribution table, the F tabulated value corresponding with 0.01 level, 4 as treatment df and 10 as error df is 5.9943.
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