15. In the figure, ABCD is a parallelogram. E is the mid-point of AB. F, G and H are points lying on CD such that DF= FG = GH= HC. BF intersect AG and EH at J and K respectively. If the area of GJKH is 12 cm2, then the area of parallelogram ABCD is G C 12 crn A E B А. 108 cm?. (B. 112 cm?. С. 120 cm?. D. 128 cm?.
15. In the figure, ABCD is a parallelogram. E is the mid-point of AB. F, G and H are points lying on CD such that DF= FG = GH= HC. BF intersect AG and EH at J and K respectively. If the area of GJKH is 12 cm2, then the area of parallelogram ABCD is G C 12 crn A E B А. 108 cm?. (B. 112 cm?. С. 120 cm?. D. 128 cm?.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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
Transcribed Image Text:15. In the figure, ABCD is a parallelogram. E is the mid-point of AB. F, G and H are points lying on CD
such that DF = FG = GH=HC. BF intersect AG and EH at J and K respectively. If the area of GJKH
is 12 cm?, then the area of parallelogram ABCD is
%3D
G
C
12 cm
A
A. 108 cm?.
(B) 112 cm?.
С.
120 cm?.
D.
128 cm?.
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