15. In how many ways can the 8 members of the committee be chosen from 15 senior and 10 junior students if there must be 5 senior students? A. 45 B. 6,435 C. 360,360 D. 1,081,575

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Eight members of the committee will be chosen from 15 senior and 10 junior student.
14. How will you represent the number of combinations in #13?
A. N = C(15,8)
B. N = C(10,8)
C. N = C(15,8) · C(10,8)
D. N = C(15,5) · C(10,3)
15. In how many ways can the 8 members of the committee be chosen from 15
senior and 10 junior students if there must be 5 senior students?
A. 45
B. 6,435
C. 360,360
D. 1,081,575
Transcribed Image Text:14. How will you represent the number of combinations in #13? A. N = C(15,8) B. N = C(10,8) C. N = C(15,8) · C(10,8) D. N = C(15,5) · C(10,3) 15. In how many ways can the 8 members of the committee be chosen from 15 senior and 10 junior students if there must be 5 senior students? A. 45 B. 6,435 C. 360,360 D. 1,081,575
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