15. If we double the radius of a right circular cone, what effect does that have on the volume? Explain your answer.

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Question 15: Volume Change in a Right Circular Cone

**Question:**
If we double the radius of a right circular cone, what effect does that have on the volume? Explain your answer.

#### Explanation:
When considering the volume of a right circular cone, it is important to remember the formula for the volume:

\[ V = \frac{1}{3} \pi r^2 h \]

Where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.

If we double the radius of the cone, the new radius \( r_{\text{new}} \) becomes \( 2r \).

Substituting \( 2r \) into the volume formula:

\[ V_{\text{new}} = \frac{1}{3} \pi (2r)^2 h \]

This simplifies to:

\[ V_{\text{new}} = \frac{1}{3} \pi (4r^2) h \]
\[ V_{\text{new}} = 4 \left( \frac{1}{3} \pi r^2 h \right) \]
\[ V_{\text{new}} = 4V \]

Therefore, if we double the radius of a right circular cone, the volume increases by a factor of four. This means the volume of the cone becomes four times larger.
Transcribed Image Text:### Question 15: Volume Change in a Right Circular Cone **Question:** If we double the radius of a right circular cone, what effect does that have on the volume? Explain your answer. #### Explanation: When considering the volume of a right circular cone, it is important to remember the formula for the volume: \[ V = \frac{1}{3} \pi r^2 h \] Where: - \( V \) is the volume, - \( r \) is the radius of the base, - \( h \) is the height of the cone. If we double the radius of the cone, the new radius \( r_{\text{new}} \) becomes \( 2r \). Substituting \( 2r \) into the volume formula: \[ V_{\text{new}} = \frac{1}{3} \pi (2r)^2 h \] This simplifies to: \[ V_{\text{new}} = \frac{1}{3} \pi (4r^2) h \] \[ V_{\text{new}} = 4 \left( \frac{1}{3} \pi r^2 h \right) \] \[ V_{\text{new}} = 4V \] Therefore, if we double the radius of a right circular cone, the volume increases by a factor of four. This means the volume of the cone becomes four times larger.
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