15. For the network of Fig. 9.80: a. Determine re b. Find A,= V/V c. Calculate Z d. Determine f,Se and f e. Determine the low cutoff frequency. Sketch the asymptotes.of the-Bode-plot-defined-by-the-eutoff-froqueneoion-of-past-d) g. Sketch the low-frequency response for the amplifier usingthe results of part (e). 14 V 5 pF C- 12 pF Cw Cw- 8 pF C- 40 pF C- 8 pF 5.6 k2 68 k2 0.47 uF B= 120 0.47 uF 3.3 ka 10 k2 1.2 ka 20 uF 0.47 ul

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For the network of Fig. 9.80 :

a. Determine r e .

b. Find Avmid = Vo>Vi.

c. Calculate Z i .

d. Determine fLS

, fLC, and fLE

.

e. Determine the low cutoff frequency.

f. Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (d).

g. Sketch the low-frequency response for the amplifier using the results of part (e).

10:02 O
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15. For the network of Fig. 9.80:
a. Determine r.
b. Find A, = Vo/Vi-
c. Calculate Z.
d. Determine fLe fLe and fLe
e. Determine the low cutoff frequency.
f. Sketch the asymptofes of the Bede plet defined-by the euteff-frequencies-ef part (d)-
g. Sketch the low-frequency response for the amplifier usingAhe results of part (e).
1489
Lyka
14 V
6 1489
Cw, = 5 pF Che = 12 pF
Cw, = 8 pF Che = 40 pF
Ce = 8 pF
TIT
25.6 k2
68 k2
0.47 µF
B = 120
0.47 uF
3.3 k2
10 k2
= 20 µF
K
1.2 k2
0.47 µF
Chrictonb
20 others
Joy Balondo left
C14
Transcribed Image Text:10:02 O M E *Electronic Device & Circuit The Il meet.google.com is sharing your screen. Stop sharing Hide O File | C:/Users/cspc/OneDrive/Desktop/Electronic%20Device%20&%20Circuit%20Theory%2011th%20Eddition.pdf (D Page view A Read aloud V Draw 9 Highlight v O Erase Contents 624 of 927 You 15. For the network of Fig. 9.80: a. Determine r. b. Find A, = Vo/Vi- c. Calculate Z. d. Determine fLe fLe and fLe e. Determine the low cutoff frequency. f. Sketch the asymptofes of the Bede plet defined-by the euteff-frequencies-ef part (d)- g. Sketch the low-frequency response for the amplifier usingAhe results of part (e). 1489 Lyka 14 V 6 1489 Cw, = 5 pF Che = 12 pF Cw, = 8 pF Che = 40 pF Ce = 8 pF TIT 25.6 k2 68 k2 0.47 µF B = 120 0.47 uF 3.3 k2 10 k2 = 20 µF K 1.2 k2 0.47 µF Chrictonb 20 others Joy Balondo left C14
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