15. For all integers a, b, and c, if a b and a c then a(b+c).

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**14.** Fill in the blanks in the following proof that for all integers \( a \) and \( b \), if \( a \mid b \) then \( a \mid (-b) \).

**Proof:** Suppose \( a \) and \( b \) are any integers such that \( a \mid b \). By definition of divisibility, there exists an integer \( r \) such that \( b = ar \). By substitution,

\[ -b = -(ar) = a(-r). \]

Let \( t = -r \). Then \( t \) is an integer because \( t = (-1) \cdot r \), and both \(-1\) and \( r \) are integers. Thus, by substitution, \( -b = at \), where \( t \) is an integer, and so by definition of divisibility, \( a \mid (-b) \), as was to be shown.

**15.** For all integers \( a \), \( b \), and \( c \), if \( a \mid b \) and \( a \mid c \) then \( a \mid (b+c) \).

**16.** For all integers \( a \), \( b \), and \( c \), if \( a \mid b \) then \( a \mid c \) then \( a \mid (b-c) \).

**17.** For all integers \( a \), \( b \), \( c \), and \( d \), if \( a \mid c \) and \( b \mid d \) then \( ab \mid cd \).
Transcribed Image Text:**14.** Fill in the blanks in the following proof that for all integers \( a \) and \( b \), if \( a \mid b \) then \( a \mid (-b) \). **Proof:** Suppose \( a \) and \( b \) are any integers such that \( a \mid b \). By definition of divisibility, there exists an integer \( r \) such that \( b = ar \). By substitution, \[ -b = -(ar) = a(-r). \] Let \( t = -r \). Then \( t \) is an integer because \( t = (-1) \cdot r \), and both \(-1\) and \( r \) are integers. Thus, by substitution, \( -b = at \), where \( t \) is an integer, and so by definition of divisibility, \( a \mid (-b) \), as was to be shown. **15.** For all integers \( a \), \( b \), and \( c \), if \( a \mid b \) and \( a \mid c \) then \( a \mid (b+c) \). **16.** For all integers \( a \), \( b \), and \( c \), if \( a \mid b \) then \( a \mid c \) then \( a \mid (b-c) \). **17.** For all integers \( a \), \( b \), \( c \), and \( d \), if \( a \mid c \) and \( b \mid d \) then \( ab \mid cd \).
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