15. Find the missing measurement for the figure. 3.74 m 3,75 m O 3.34 m 1.88 m

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
icon
Concept explainers
Topic Video
Question
### Question 15: Find the Missing Measurement for the Figure

#### Problem Statement:
You are given a right triangle with the following measurements:
- One leg is labeled as \( \frac{10}{3} \) meters.
- The hypotenuse is labeled as \( \frac{25}{4} \) meters.

#### Figure Description:
The right triangle diagram is shown with:
- The vertical leg labeled as \( \frac{10}{3} \) meters.
- The hypotenuse labeled as \( \frac{25}{4} \) meters.
- The horizontal leg is missing and labeled as \( h \).

#### Answer Choices:
a) 3.74 m  
b) 3.75 m  
c) 3.34 m  
d) 1.88 m  

#### Analysis:
To find the missing measurement \( h \), use the Pythagorean Theorem \( a^2 + b^2 = c^2 \), where \( a \) and \( b \) are the legs of the right triangle, and \( c \) is the hypotenuse.

Given:
- \( a = \frac{10}{3} \)
- \( c = \frac{25}{4} \)

Calculate \( h \):
\[ h^2 + \left(\frac{10}{3}\right)^2 = \left(\frac{25}{4}\right)^2 \]

#### Detailed Calculation:
\[ h^2 + \frac{100}{9} = \frac{625}{16} \]

Clear the fractions by finding a common denominator:
\[ h^2 + \frac{1600}{144} = \frac{5625}{144} \]

Subtract \(\frac{1600}{144}\) from both sides:
\[ h^2 = \frac{5625}{144} - \frac{1600}{144} \]
\[ h^2 = \frac{4025}{144} \]

Simplify the fraction:
\[ h^2 = \frac{805}{28.8} \]
\[ h = \sqrt{\frac{4025}{144}} \]
\[ h = 4.72 \, \text{meters} \]

However, none of the answer choices match this result. Recheck the math or consider approximation if necessary.

Correct the potential mistake and retest each answer:
\[ \sqrt{\frac{4025}{144}} \
Transcribed Image Text:### Question 15: Find the Missing Measurement for the Figure #### Problem Statement: You are given a right triangle with the following measurements: - One leg is labeled as \( \frac{10}{3} \) meters. - The hypotenuse is labeled as \( \frac{25}{4} \) meters. #### Figure Description: The right triangle diagram is shown with: - The vertical leg labeled as \( \frac{10}{3} \) meters. - The hypotenuse labeled as \( \frac{25}{4} \) meters. - The horizontal leg is missing and labeled as \( h \). #### Answer Choices: a) 3.74 m b) 3.75 m c) 3.34 m d) 1.88 m #### Analysis: To find the missing measurement \( h \), use the Pythagorean Theorem \( a^2 + b^2 = c^2 \), where \( a \) and \( b \) are the legs of the right triangle, and \( c \) is the hypotenuse. Given: - \( a = \frac{10}{3} \) - \( c = \frac{25}{4} \) Calculate \( h \): \[ h^2 + \left(\frac{10}{3}\right)^2 = \left(\frac{25}{4}\right)^2 \] #### Detailed Calculation: \[ h^2 + \frac{100}{9} = \frac{625}{16} \] Clear the fractions by finding a common denominator: \[ h^2 + \frac{1600}{144} = \frac{5625}{144} \] Subtract \(\frac{1600}{144}\) from both sides: \[ h^2 = \frac{5625}{144} - \frac{1600}{144} \] \[ h^2 = \frac{4025}{144} \] Simplify the fraction: \[ h^2 = \frac{805}{28.8} \] \[ h = \sqrt{\frac{4025}{144}} \] \[ h = 4.72 \, \text{meters} \] However, none of the answer choices match this result. Recheck the math or consider approximation if necessary. Correct the potential mistake and retest each answer: \[ \sqrt{\frac{4025}{144}} \
Expert Solution
steps

Step by step

Solved in 2 steps with 6 images

Blurred answer
Knowledge Booster
Application of Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning