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15. Factor the polynomial. 1252 + 27 O (5x – 3)(25x² +15z – 9) О б2 + 3) (2527 -152 + 9) О(ба — 3) (25х? - 15х — 9) О ба — 3) (2522 —152 + 9) O (5x + 3)(25x² +15z + 9) Q O 16. Find the inverse of the function. y = 10z2 – 4 Oy = i10v7 - 4 I+4 y =+ 10 Oy=i4Vã+10 Oy = 2z10 +4 J=V- 1 y = 10

15. Factor the polynomial. 1252 + 27 O (5x – 3)(25x² +15z – 9) О б2 + 3) (2527 -152 + 9) О(ба — 3) (25х? - 15х — 9) О ба — 3) (2522 —152 + 9) O (5x + 3)(25x² +15z + 9) Q O 16. Find the inverse of the function. y = 10z2 – 4 Oy = i10v7 - 4 I+4 y =+ 10 Oy=i4Vã+10 Oy = 2z10 +4 J=V- 1 y = 10

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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15. Factor the polynomial. 125z + 27 (5x – 3) (25x? + 15z – 9) (5a + 3) (25a? – 15» + 9) (52 – 3) (25a? – 15 – 9) (52 – 3) (25a – 15» + 9) (5x + 3) (2522 + 15æ + 9) 16. Find the inverse of the function. y = 10z2 – 4 y = i10va – 4 r+4 y =1 10 y = 14/a + 10 O y = 2x10 +4 1. y = 10 -
Transcribed Image Text:15. Factor the polynomial. 125z + 27 (5x – 3) (25x? + 15z – 9) (5a + 3) (25a? – 15» + 9) (52 – 3) (25a? – 15 – 9) (52 – 3) (25a – 15» + 9) (5x + 3) (2522 + 15æ + 9) 16. Find the inverse of the function. y = 10z2 – 4 y = i10va – 4 r+4 y =1 10 y = 14/a + 10 O y = 2x10 +4 1. y = 10 -
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