15. [0/0.43 Points] DETAILS PREVIOUS ANSWERS LARPCALCCC3 4.1.502.XP. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A sprinkler on a golf green is set to spray water over a distance of 20 meters and to rotate through an angle of 160°. Draw a diagram that shows the region that can be irrigated with the sprinkler. Find the area of the region. (Round your answer to two decimal places.) x m? 558.73

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Problem Statement:**

A sprinkler on a golf green is set to spray water over a distance of 20 meters and to rotate through an angle of 160°. Draw a diagram that shows the region that can be irrigated with the sprinkler. Find the area of the region. (Round your answer to two decimal places.)

**Details:**

- Distance: 20 meters
- Angle: 160°

**Solution:**

1. **Concept:**
   The sprinkler's area of irrigation is a sector of a circle with a radius of 20 meters and a central angle of 160°. 

2. **Calculation:**
   The formula for the area \( A \) of a sector with radius \( r \) and angle \( \theta \) in degrees is:
   \[
   A = \frac{\theta}{360} \times \pi r^2
   \]

3. **Substitute the values:**
   \[
   A = \frac{160}{360} \times \pi \times 20^2
   \]
   \[
   A = \frac{4}{9} \times \pi \times 400
   \]
   \[
   A \approx 558.83 \, \text{m}^2
   \]

The answer provided in the image incorrectly shows 558.73 m², marked with an error. The correct rounded area to two decimal places is 558.83 m².

**Visual Representation:**

- The diagram would generally show a circle with radius 20 meters, with a shaded sector representing the 160° angle. 
- The center of the circle is the location of the sprinkler, and the radius lines mark the boundary of the irrigated region.
Transcribed Image Text:**Problem Statement:** A sprinkler on a golf green is set to spray water over a distance of 20 meters and to rotate through an angle of 160°. Draw a diagram that shows the region that can be irrigated with the sprinkler. Find the area of the region. (Round your answer to two decimal places.) **Details:** - Distance: 20 meters - Angle: 160° **Solution:** 1. **Concept:** The sprinkler's area of irrigation is a sector of a circle with a radius of 20 meters and a central angle of 160°. 2. **Calculation:** The formula for the area \( A \) of a sector with radius \( r \) and angle \( \theta \) in degrees is: \[ A = \frac{\theta}{360} \times \pi r^2 \] 3. **Substitute the values:** \[ A = \frac{160}{360} \times \pi \times 20^2 \] \[ A = \frac{4}{9} \times \pi \times 400 \] \[ A \approx 558.83 \, \text{m}^2 \] The answer provided in the image incorrectly shows 558.73 m², marked with an error. The correct rounded area to two decimal places is 558.83 m². **Visual Representation:** - The diagram would generally show a circle with radius 20 meters, with a shaded sector representing the 160° angle. - The center of the circle is the location of the sprinkler, and the radius lines mark the boundary of the irrigated region.
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