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15 Ω 24 N ia 10 Ω ww 19N 12 V 25 N ia 10 V ic O (10)(i. – ia) – (12)(ic – is) + (25)(ic – ia) = 0 O (10)(ic – ia) + (25)(ic – ia) – 12 = 0 O (10)(ie) + (25)(ic – ia) + 12 = 0 O (10)(ic – ia) – (12)(ic – is) + 25 = 0 +. +, ww

15 Ω 24 N ia 10 Ω ww 19N 12 V 25 N ia 10 V ic O (10)(i. – ia) – (12)(ic – is) + (25)(ic – ia) = 0 O (10)(ic – ia) + (25)(ic – ia) – 12 = 0 O (10)(ie) + (25)(ic – ia) + 12 = 0 O (10)(ic – ia) – (12)(ic – is) + 25 = 0 +. +, ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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15 0 ww ia 24 0 10 Ω ww 19 N 12 V 25 0 10 V is O (10)(ic – ia) – (12)(ic – is) + (25)(ic – ia) = 0 %3D O (10)(ic – ia) + (25)(i. – ia) – 12 = 0 O (10)(ic) + (25)(ic – ia) + 12 = 0 O (10)(ic – ia) – (12)(ic – is) + 25 = 0 -
Transcribed Image Text:15 0 ww ia 24 0 10 Ω ww 19 N 12 V 25 0 10 V is O (10)(ic – ia) – (12)(ic – is) + (25)(ic – ia) = 0 %3D O (10)(ic – ia) + (25)(i. – ia) – 12 = 0 O (10)(ic) + (25)(ic – ia) + 12 = 0 O (10)(ic – ia) – (12)(ic – is) + 25 = 0 -
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