15) The angle of elevation from ground level to the top of a building is 62°. If the observer is standing 300 feet from the building, how tall is the building?

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Problem Statement:**

The angle of elevation from ground level to the top of a building is 62°. If the observer is standing 300 feet from the building, how tall is the building?

**Explanation:**

This is a trigonometry problem involving the tangent function. The angle of elevation is the angle between the horizontal ground and the line of sight to the top of the building. To find the height of the building, use the tangent of the angle of elevation.

**Mathematical Solution:**

Given:
- Angle of elevation, θ = 62°
- Distance from the building, d = 300 feet

To find the height, h, use the formula:
\[
\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
\]

Substitute the values:
\[
\tan(62°) = \frac{h}{300}
\]

Rearrange to solve for h:
\[
h = 300 \times \tan(62°)
\]

Calculate the height using a calculator to find the tangent of 62°.

This approach will yield the height of the building in feet.
Transcribed Image Text:**Problem Statement:** The angle of elevation from ground level to the top of a building is 62°. If the observer is standing 300 feet from the building, how tall is the building? **Explanation:** This is a trigonometry problem involving the tangent function. The angle of elevation is the angle between the horizontal ground and the line of sight to the top of the building. To find the height of the building, use the tangent of the angle of elevation. **Mathematical Solution:** Given: - Angle of elevation, θ = 62° - Distance from the building, d = 300 feet To find the height, h, use the formula: \[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \] Substitute the values: \[ \tan(62°) = \frac{h}{300} \] Rearrange to solve for h: \[ h = 300 \times \tan(62°) \] Calculate the height using a calculator to find the tangent of 62°. This approach will yield the height of the building in feet.
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