15 kN 30 kN/m Determine the maximum deflection of the cantilevered beam. The beam is made of material having an E = 200 GPa and I = 65 • 106 mmª. A -1.5 m- 1.5 m Incorrect Umar Number Correct Answer: 12.916154 ± 2.0%

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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15 kN
30 kN/m
Determine the maximum deflection of the cantilevered beam. The beam is made of
material having an E = 200 GPa and I = 65 * 106 mm4.
A
-1.5 m-
- 1.5 m
Incorrect
Umar
Number
Correct Answer: 12.916154 + 2.0%
Transcribed Image Text:15 kN 30 kN/m Determine the maximum deflection of the cantilevered beam. The beam is made of material having an E = 200 GPa and I = 65 * 106 mm4. A -1.5 m- - 1.5 m Incorrect Umar Number Correct Answer: 12.916154 + 2.0%
Deflection
Elastic Curve
Beam
Slope
P
- PL
-Px
Vmax
-PL
(3L – x)
v =
Omax
2EI
Umax
3EI
6EI
O max
-Px?
(3L – 2x) 0 < x< L/2
12EI
V =
Vmax
-PL?
-5PL3
Omax
8EI
Vmax
48EI
-PL?
(6x – L) L/2 << L
48EI
v =
emax
-wx?
(x² – 4Lx + 6L)
24EI
-wL?
-wL
Umax
v =
Omax
Umax
8EI
6EI
max
.Omax
MoL
MəL?
Mox?
V =
Omax
Umax
2EI
2EI
Mo Vmax
EI
-wx?
(x² – 2Lx + L²)
V =
24EI
Vmax
0 <x< L/2
-wL
-7wL
Omax
Umax
384EI
-wL
48EI
v =
(8x – L)
max
384EI
L/2 < x < L
Wo
-w,L
-wo.x?
-woL
Omax
Umax
(10L – 101?x + 5Lx? – x³)
v =
Umax
30EI
120EIL
24EI
0 max
||
Transcribed Image Text:Deflection Elastic Curve Beam Slope P - PL -Px Vmax -PL (3L – x) v = Omax 2EI Umax 3EI 6EI O max -Px? (3L – 2x) 0 < x< L/2 12EI V = Vmax -PL? -5PL3 Omax 8EI Vmax 48EI -PL? (6x – L) L/2 << L 48EI v = emax -wx? (x² – 4Lx + 6L) 24EI -wL? -wL Umax v = Omax Umax 8EI 6EI max .Omax MoL MəL? Mox? V = Omax Umax 2EI 2EI Mo Vmax EI -wx? (x² – 2Lx + L²) V = 24EI Vmax 0 <x< L/2 -wL -7wL Omax Umax 384EI -wL 48EI v = (8x – L) max 384EI L/2 < x < L Wo -w,L -wo.x? -woL Omax Umax (10L – 101?x + 5Lx? – x³) v = Umax 30EI 120EIL 24EI 0 max ||
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