15 In the diagram below of right triangle KTW, KW = 6, KT= 5, and mZKTW = 90. W 6. K What is the measure of ZK, to the nearest minute?

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**Mathematics Problem: Right Triangle Angle Calculation**

**Problem Statement:**
In the diagram below of right triangle \(KTW\), \(KW = 6\), \(KT = 5\), and \(m\angle KTW = 90^\circ\).

\[
\begin{array}{ccccc}
 &&W & \\
 &&| & \\
 &&| &6 \\
T& \underline{\blacksquare} &\hspace{0.5cm} & \_  \_ \_ \_ \_ \_  &_K\,5
\end{array}
\]

**Question:**
What is the measure of \( \angle K \), to the nearest minute?

### Explanation of Diagram:
The diagram represents a right-angled triangle \(KTW\) where:
- \(W\) is the vertex opposite the right angle.
- \( \overline{KW} \) is the hypotenuse with a length of 6 units.
- \( \overline{KT} \) is one leg of the triangle with a length of 5 units.
- \( \overline{TW} \) forms the height of the triangle.

### Solution:
To find the measure of \( \angle K \), we use trigonometric functions. The angle \( \angle K \) can be calculated using the cosine function:
\[ \cos(\mathbf{\theta}) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \]

For \( \angle K \):
\[ \cos(K) = \frac{KT}{KW} = \frac{5}{6} \]

Using the inverse cosine function (arccos),
\[ K = \cos^{-1} \left( \frac{5}{6} \right) \]

### Steps to Calculate:
1. Calculate the arccosine value using a calculator.
2. Convert the result from degrees to the nearest minute.

### Calculation:
Using a scientific calculator,
\[ K \approx 33.5573^\circ \]

To convert to degrees and minutes:
\[ 33.5573^\circ = 33^\circ + 0.5573^\circ \]

Convert the decimal part to minutes:
\[ 0.5573^\circ \times 60 \approx 33.438 \text{ minutes} \]

Thus,
\[ K \approx 33^\circ 33' \]

### Final
Transcribed Image Text:**Mathematics Problem: Right Triangle Angle Calculation** **Problem Statement:** In the diagram below of right triangle \(KTW\), \(KW = 6\), \(KT = 5\), and \(m\angle KTW = 90^\circ\). \[ \begin{array}{ccccc} &&W & \\ &&| & \\ &&| &6 \\ T& \underline{\blacksquare} &\hspace{0.5cm} & \_ \_ \_ \_ \_ \_ &_K\,5 \end{array} \] **Question:** What is the measure of \( \angle K \), to the nearest minute? ### Explanation of Diagram: The diagram represents a right-angled triangle \(KTW\) where: - \(W\) is the vertex opposite the right angle. - \( \overline{KW} \) is the hypotenuse with a length of 6 units. - \( \overline{KT} \) is one leg of the triangle with a length of 5 units. - \( \overline{TW} \) forms the height of the triangle. ### Solution: To find the measure of \( \angle K \), we use trigonometric functions. The angle \( \angle K \) can be calculated using the cosine function: \[ \cos(\mathbf{\theta}) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \] For \( \angle K \): \[ \cos(K) = \frac{KT}{KW} = \frac{5}{6} \] Using the inverse cosine function (arccos), \[ K = \cos^{-1} \left( \frac{5}{6} \right) \] ### Steps to Calculate: 1. Calculate the arccosine value using a calculator. 2. Convert the result from degrees to the nearest minute. ### Calculation: Using a scientific calculator, \[ K \approx 33.5573^\circ \] To convert to degrees and minutes: \[ 33.5573^\circ = 33^\circ + 0.5573^\circ \] Convert the decimal part to minutes: \[ 0.5573^\circ \times 60 \approx 33.438 \text{ minutes} \] Thus, \[ K \approx 33^\circ 33' \] ### Final
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