15 51 :- -/- -1- :- ーによ -1- イーキーーュ ナー ートー- ー ーー III II III IL 1,0 15 15 -1 ーャー- -15 r2 + 13x + 42 f(x): %3D r2 14x +45 1. lim f(z) %3D 2. lim f(z) 3. lim f(z) %3D 4. lim f(r) I5+ %3D

Q: Differentiate 3x-1 2x + 3 with respect to 'x'.

A:

Q: Limit メ+5 メ→-5 |Jx-っ-4

A: To findlimx→-5x+5|x2-9|-4

Q: f(x,y)=9-x^2- y^2

A: We have to find standard form of the given equation and then identify the surface

Q: Evaluate: /1-x*dx 3 A +C (B x4) 2 +C 3 3 D--(1-x*) 2 +C E None

A:

Q: (x^(2)-4y)/(2) x=4 y=-3

A:

Q: F(x)=x^2-5 subtract 1 then square

A:

Q: Evaluate intergral  (ax)/(x2-bx) where a and b are constants

A: The given integral is ∫axx2-bxdx.

Q: ツ End ly rー tanx Dソ= (mnx) cotx ナ (cotx) %3D

A: We differentiate the function using logarithms.

Q: if y= 3t^2+t+2, x=(2t-3)^3 then dy\dt= 6t+5 false true

A:

Q: YA 7) 3 X+4 3 y>}x-1 2 432 -2 -1 -4 2 3 4 -2 -3 4 -5

A: The given inequality is: y≤-34x+4y>12x-1

Q: 1. 4x (7x - 10) 4. -7y'y - 2y - 3y - 3)

A: 1) 4x2(7x-10) =  4x2(7x-10) = (4x2)(7x)+(4x2)(−10) = 28x3−40x2    4x2(7x-10) = 28x3−40x2 is the…

Q: =a(x-1)^2+2 passes through the points (10,-160) A=

A: NOTE: Refresh your page if you can't see any equations. . the point (10,-160) is on the graph so…

Q: 5. a) Find the volume of the solid bounded by the paraboloid z= 2(x? + y²) +3 and the cylinder x? +…

A: (a)  Find the volume of the solid bounded by the paraboloid z=2x2+y2+3 and the cylinder x2+y2=1 and…

Q: Eliminate the arbitrary constants: x^2y=1+cx

A: Introduction: The anti-derivatives of a function can be found using integral calculus. These…

Q: Find real numbers and such that 2.x – 3iy + 4ix – 2 y – 5–10ix = x + y – iy + 2-(3– x)i

A:

Q: If f(x) = 3x- x^2+2, find the value of: a.) f(0) b.) f(3) c.) f(-3) d.) f(-7) e.) f(3/2)

A: Given: fx=3x-x2+2 To find: a.) f(0) b.) f(3) c.) f(-3) d.) f(-7) e.) f32

Q: 1- x 5. dx VI - r

A:

Q: Find the value of x that results in a maximum value of y if -2=x^2+y^2-4x+4y?

A: The given equation is -2=x2+y2-4x+4y. To find the value of x that results in a maximum value of y,…

Q: (2) [D² - (a + b)D + ab]y = 0. = 0, a and b being real and unequal

A: Given data:- D2-(a+b)D+ab)y=0 a and b are real and unequal

Q: Draw y² = f(x) 1+ (1,-1) 2 (2.5,1)

A: We have draw the graph of y2=f(x)The procedure is given below

Q: - 10x²y* 15x'y-3 Simplify: 7,,-3

A: Given,  −10x2y415x7y−3Formula→anam=an−m