Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Problem 4:**
Evaluate the integral \( \int_{7}^{15} f'(t) \, dt \), where \( f' \) is continuous on the interval \([7, 15]\), with the conditions \( f(7) = 5 \) and \( f(15) = 11 \).
**Explanation:**
This is a problem involving the evaluation of a definite integral of the derivative of a function. The Fundamental Theorem of Calculus states that for a continuous function \( f \) on \([a, b]\), if \( F \) is an antiderivative of \( f \), then:
\[ \int_{a}^{b} f'(t) \, dt = F(b) - F(a) \]
In this case, since \( f' \) is the derivative of \( f \), the integral simplifies to:
\[ f(15) - f(7) = 11 - 5 = 6 \]
Thus, the value of the integral is 6.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9a46fe1-36bd-4e69-be33-e748526575ae%2Fe193bbc9-9274-43a8-818e-71d18910975c%2F4b8x3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 4:**
Evaluate the integral \( \int_{7}^{15} f'(t) \, dt \), where \( f' \) is continuous on the interval \([7, 15]\), with the conditions \( f(7) = 5 \) and \( f(15) = 11 \).
**Explanation:**
This is a problem involving the evaluation of a definite integral of the derivative of a function. The Fundamental Theorem of Calculus states that for a continuous function \( f \) on \([a, b]\), if \( F \) is an antiderivative of \( f \), then:
\[ \int_{a}^{b} f'(t) \, dt = F(b) - F(a) \]
In this case, since \( f' \) is the derivative of \( f \), the integral simplifies to:
\[ f(15) - f(7) = 11 - 5 = 6 \]
Thus, the value of the integral is 6.
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