15 4. Evaluate f'(t) dt, wheref' is continuous on [7, 15], f(7) =5, andf(15) =11.

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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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**Problem 4:**

Evaluate the integral \( \int_{7}^{15} f'(t) \, dt \), where \( f' \) is continuous on the interval \([7, 15]\), with the conditions \( f(7) = 5 \) and \( f(15) = 11 \).

**Explanation:**

This is a problem involving the evaluation of a definite integral of the derivative of a function. The Fundamental Theorem of Calculus states that for a continuous function \( f \) on \([a, b]\), if \( F \) is an antiderivative of \( f \), then:

\[ \int_{a}^{b} f'(t) \, dt = F(b) - F(a) \]

In this case, since \( f' \) is the derivative of \( f \), the integral simplifies to:

\[ f(15) - f(7) = 11 - 5 = 6 \]

Thus, the value of the integral is 6.
Transcribed Image Text:**Problem 4:** Evaluate the integral \( \int_{7}^{15} f'(t) \, dt \), where \( f' \) is continuous on the interval \([7, 15]\), with the conditions \( f(7) = 5 \) and \( f(15) = 11 \). **Explanation:** This is a problem involving the evaluation of a definite integral of the derivative of a function. The Fundamental Theorem of Calculus states that for a continuous function \( f \) on \([a, b]\), if \( F \) is an antiderivative of \( f \), then: \[ \int_{a}^{b} f'(t) \, dt = F(b) - F(a) \] In this case, since \( f' \) is the derivative of \( f \), the integral simplifies to: \[ f(15) - f(7) = 11 - 5 = 6 \] Thus, the value of the integral is 6.
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