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[15 -4] 24 -5 Find S, D, and S-1 such that A = SDS-¹. Let A = S = , D = 0 S-1 || 81

[15 -4] 24 -5 Find S, D, and S-1 such that A = SDS-¹. Let A = S = , D = 0 S-1 || 81

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Let \( A = \begin{bmatrix} 15 & -4 \\ 24 & -5 \end{bmatrix} \). Find \( S \), \( D \), and \( S^{-1} \) such that \( A = SDS^{-1} \). \[ S = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix}, \quad D = \begin{bmatrix} \boxed{} & 0 \\ 0 & \boxed{} \end{bmatrix}, \quad S^{-1} = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix}. \]
Transcribed Image Text:Let \( A = \begin{bmatrix} 15 & -4 \\ 24 & -5 \end{bmatrix} \). Find \( S \), \( D \), and \( S^{-1} \) such that \( A = SDS^{-1} \). \[ S = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix}, \quad D = \begin{bmatrix} \boxed{} & 0 \\ 0 & \boxed{} \end{bmatrix}, \quad S^{-1} = \begin{bmatrix} \boxed{} & \boxed{} \\ \boxed{} & \boxed{} \end{bmatrix}. \]
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