15-240° V C n 1520° V lat 15-120° V Vca b ibl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180) (Round decimal answers to 2 digits) ial ibl = id = A A A Vab =U Ubc = Vca = V V ° V -8-j8 N Vab Uhe -8-j8N-8-j8 N
15-240° V C n 1520° V lat 15-120° V Vca b ibl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180) (Round decimal answers to 2 digits) ial ibl = id = A A A Vab =U Ubc = Vca = V V ° V -8-j8 N Vab Uhe -8-j8N-8-j8 N
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter8: Symmetrical Components
Section: Chapter Questions
Problem 8.1MCQ: Positive-sequence components consist of three phasors _________ with magnitudes and _________ phase...
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Transcribed Image Text:15-240° V
C
n
1520° V
lat
15-120° V
Vca
b
ibl
Find the line currents and line-to-line voltages.
(Positive magnitudes) (Phase angles between ±180) (Round decimal answers to 2 digits)
ial
ibl =
id
=
A
A
A
Vab
=U
Ubc =
Vca
=
V
V
° V
-8-j8 N
Vab
Uhe
-8-j8N-8-j8 N
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