15- 2 NO(g) + O2(g) 2 NO2(g) For the reaction above, the rate constant at 380°C for the forward reaction is 2.6x10³ liter/mole?-sec and this reaction is first order in O2 and second order in NO. The rate constant for the reverse reaction at 380°C is 4.1 liter/mole-sec and this reaction is second order in NO2. (a) Write the equilibrium expression for the reaction as indicated by the equation above and calculate the numerical value for the equilibrium constant at 380°C. (b) What is the rate of the production of NO2 at 380°C if the concentration of NO is 0.0060 mole/liter and the concentration of O2 is 0.29 mole/liter? (c) The system above is studied at another temperature. A 0.20 mole sample of NO2 is placed in a 5.0 liter container and allowed to come to equilibrium. When equilibrium is reached, 15% of the original NO2 has decomposed to NO and O2. Calculate the value for the equilibrium constant at the second temperature.

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Process Flow Diagram

A process flow diagram is a representation of various components, how they are arranged, and in what manner or sequence they work in correspondence to each other. It is a graphical way of representing a process.