14NT 1. x = 3t –1 and y = -t+ 2 for 0

Q: Evaluate for: x = -2, y = 4, and z = 16 * J16 - (y +x)? |-2| 6. -14 O 2 18

A: To solve the given expression with  x =- 2, y = 4 And z = 16

Q: (r2+2rt-4t2)dr-(r2-8rt-4t2)dt=0

A:

Q: /| (9x + y – 2z) dS. Is Evaluate S: z = x + 0 < x< 4, 0 <y< 7

A: Given: ∫∫S9x+y-2zdSS:z=x+y2, 0≤x≤4, 0≤y≤7

Q: Evaluate | (r + y)ds, c : x 3t, y = - 3t + 3, for 0 <t< 3.

A: Given: ∫C(x+y)ds, C: x=3t, y=-3t+3, for 0≤t≤3

Q: Find for the following: y = 4x° – 2x 322 – 4x – 14

A: Recall: d[a f(x)± bg(x)]dx=a d[f(x)]dx± b d[g(x)]dx; where 'a' and 'b' are constants. dxndx= n xn-1…