? → 147N + 0-1e a) it is n (mass # : 1; charge:0) b) no right answer c) it is Br (mass # : 76; protons: 35) d) it is C (mass #: 14; protons 6) e) it is e ( mass #: 0 ; charge +1)
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? → 147N + 0-1e
a) it is n (mass # : 1; charge:0)
b) no right answer
c) it is Br (mass # : 76; protons: 35)
d) it is C (mass #: 14; protons 6)
e) it is e ( mass #: 0 ; charge +1)
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- 10. Use Coulomb's Law to solve the following problems www ww ww a) Four charges are placed in the plane as indicated q1 92 = -5 nC in rz = j, 10 nC in r, = i + 2j, 94 = 20 nC in ra = -i – 2j 93 = -2 nC in r3 = -2i + 2j force and Calculate the total acting on in direction and 92 magnitude, also draw the free body diagram.32) The charge, and mass, of the proton are which of the following values? a) +1.6 x 1019 C, m = 1.67 x 10-27 kg; b) -1.6 x 1019C, 9.11 x 10³' kg; c) 0, 1.67 x 1027 kg; and d) 3.2 x 1019 C, m = 1.8 x 1030 kg. 3) A proton is placed in a uniform electric field of 2.75 x 103 N/C. Calculate the following: i) magnitude of the electric force exerted on the proton; i) the proton's resultant acceleration; and ii) the speed of the proton, 1 usec after being released in the field, assuming it starts from rest. Show all work for credit. a) F(p) = 4.4 x 10:16 N, a(p) = 2.75 x 10" m/s², v(p) = 2.75 x 10' m/s; b) F(p) = 20 x 1018 N, a(p) = 1.2 x 101º m/s², v(p) = 1.4 x 10ʻ m/s; c) F(p) = 8 x 1016 N, a(p) = 4.8 x 10" m/s², v(p) = 2.63 x 105 m/s; or d) F(p) = 120 x 1019 N, a(p) = 63 x 10° m/s², v(p) = 8 x 10³ m/s. %3D %3D %3D %3D
- #17 Infinite Line Charge Supposse the electric field strength 1.00 m from a line charge is 20,000 N/C. What is the electric field strength 0.500 m from the same line charge? A. 5,000 N/C B. 10,000 N/C C. 40,000 N/C D. 80,000 N/C1. When point charges q = +8 4 µC and q2 = + 5,6µC are brought near each other, each experiences a repulsive force of magnitude 0.77. N. Determine the distance between the two charges. [ Given Data, Coulomb's Constant, Ke = 8.99X10 Nm2/C21 The distance between the two charges = m. [2 marks] 2.An electric field of 250000 N/C points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge 7:0HC at this spot? The magnitude of the force = N and direction = from the charge. [2 marks)5.) What is the x-component of the electric field corresponding to a potential V(x.y) = -3x +7xy -3y? a.) 7x - 3, b.) 3x² -7y, c.) 6x - 7y, d.) -6x + 7y, e.) -7x + 3
- 2) Calculate the force exerted on Q1 by Q2 and Q3 and state which direction the charge will move, a = 1.75x10-15m , b = 15x10-15m and Q1 = Q2 = Q3 = 1.602x10-19C. a Q1 Q3 3) Calculate Work done placing a positive charge (Q1=3.4x10-12 C) a distance of 1nm away from another positive charge Q2=5x1011 C.2) Consider a beam of electron so that each has a kinetic energy of 1.95 x 10-15 J. We want to set up an electric field parallel to the beam that stops the electrons after they've crossed a distance of 0.14m? What is the electric field strength that we need?Two charged particles, held not too far from each other, are released. As they move, the electric force on each particle increases. So, the particles must have A) the same mass B) charges of opposite signs C) the same size D) charges of the same sign E) impossible to answer without additional information