′′−144y=4000t^(2)e^(12t)+62. If yp is the particular solution of the equation above obtained by the method of coefficients to be determined, then the value of yp(1/12) is:
′′−144y=4000t^(2)e^(12t)+62. If yp is the particular solution of the equation above obtained by the method of coefficients to be determined, then the value of yp(1/12) is:
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the differential equation
y′′−144y=4000t^(2)e^(12t)+62.
If yp is the particular solution of the equation above obtained by the method of coefficients to be determined, then the value of yp(1/12) is:
a. 125e/3888−751/72
b.125e/3888−31/72
c.125e/3888+1049/72
d.125e/3888+689/72
e.125e/3888+329/72.
Transcribed Image Text:12t
y" – 144y = 4000t°e + 62.
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