′′−144y=4000t^(2)e^(12t)+62. If yp is the particular solution of the equation above obtained by the method of coefficients to be determined, then the value of yp(1/12) is:

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Consider the differential equation
y′′−144y=4000t^(2)e^(12t)+62.
If yp is the particular solution of the equation above obtained by the method of coefficients to be determined, then the value of yp(1/12) is:

a. 125e/3888−751/72
b.125e/3888−31/72
c.125e/3888+1049/72
d.125e/3888+689/72
e.125e/3888+329/72.
12t
y" – 144y = 4000t°e + 62.
Transcribed Image Text:12t y" – 144y = 4000t°e + 62.
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